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12
说明: c编写的链表连接函数,上课时学的,上传试试 (c write the list to connect function, class, learn, try uploading)
- 2010-07-08 15:27:22下载
- 积分:1
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listnode
C++中,对链表的增删改查的基本使用,值得学习(C++, on the list of CRUD basic use, it is worth learning)
- 2015-08-05 17:57:12下载
- 积分:1
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Lists
用模板实现了单向链表的增删改查等功能,并且适用于多种数据结构和类,简单实用,是学习和使用的绝好资料(Template to achieve a one-way linked list CRUD functions, and is suitable for a variety of data structures and classes, simple and practical, is to learn and use excellent information)
- 2014-06-02 13:36:32下载
- 积分:1
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Strassen-code
思塞恩算法
常用算法之一
算法导论提及(strassen algorithm which can run correctly)
- 2014-11-28 14:33:16下载
- 积分:1
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Joseph
说明: 约瑟夫问题,四种解法,分别是静态链表,顺序表两种和循环链表(Joseph problems, the four solution, namely a static list, order form and the cycle of two lists)
- 2010-04-23 08:20:53下载
- 积分:1
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class
拓扑排序 -打印输出计算机本科专业4年每学期的课表(Topological sort - computer printout of undergraduate curriculum of each semester for 4 years)
- 2016-12-12 14:53:46下载
- 积分:1
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astar
A*算法 1、将开始节点放入开放列表(开始节点的F和G值都视为0)
2、重复以下步骤:
在开放列表中查找具有最小F值的节点,并把查找到的节点作为当前节点
把当前节点从开放列表删除, 加入到封闭列表.
(A* algorithm 1, will begin to node placed in the and opening up list of (the began to node of the F and G values are regarded as 0) 2, repeat the the following steps: to Find a the has a the the smallest F value of the node in the the and opening up list of, and put Find a to the node as the current node current node is removed from the open list, added to the closed list.)
- 2013-04-04 11:06:42下载
- 积分:1
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lvxingshang
一个经典的旅行商问题源码,不是最优解,只是一种 思路(A classic traveling salesman problem source is not the optimal solution, just a thought)
- 2012-11-09 01:33:02下载
- 积分:1
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maze
实现经典问题老鼠迷宫,并用坐标将路径显示出来(Achieve classic problem rat maze, and coordinate with the path displayed)
- 2016-05-25 22:56:59下载
- 积分:1
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chessboard-distance
一道poj上的问题的解答,棋盘上的距离问题。即实现棋盘上从一个点移动到王,后,兵之间最短步数的解答。(A poj answers to your questions on the chessboard distance problem. That is, move from one point to the king on the board, after the shortest number of steps between the soldiers answer.)
- 2012-06-20 10:10:45下载
- 积分:1