-
kring123
克里金(Kriging)插值法又称空间自协方差最佳插值法,它是以南非矿业工程师D.G.Krige的名字命名的一种最优内插法。克里金法广泛地应用于地下水模拟、土壤制图等领域,是一种很有用的地质统计格网化方法。它首先考虑的是空间属性在空间位置上的变异分布.(Kringing smooth)
- 2020-09-16 21:57:55下载
- 积分:1
-
HLL2
计算流体力学,HLL格式的一个算例,可以直接计算,适合初学者,易懂,每步有说明。(The calculation of an example of fluid dynamics, HLL format, can be calculated directly, suitable for beginners, easy to understand each step is described.)
- 2021-04-21 01:38:49下载
- 积分:1
-
grey
灰色关联度分析是基于灰色系统的灰色过程, 进行因素间时间序列的比较来确定哪些是影响大的主导因素, 是一种动态过程的研究。(Grey Relational Analysis is based on gray gray process, the comparison of the time series between the factors to determine what affect the the big dominant factor, is a dynamic process.)
- 2012-08-25 00:27:37下载
- 积分:1
-
Matrix
很好用的有关矩阵的各种操作,包括求逆,特征值,特征向量,svd分解等(good part of the matrix of various operations including inverse, eigenvalues, eigenvectors, svd decomposition, etc.)
- 2020-10-31 16:39:55下载
- 积分:1
-
delta-master
非圆形离散元程序,通过采用非圆形颗粒实现康转动性能(Non-circular discrete element program, through the use of non-spherical particles achieve Kang rotation capability)
- 2016-05-18 11:10:53下载
- 积分:1
-
line_guiyi
数据归一化处理,对数据进行一个标准化处理,将各个不同单位的变量,转换成无量纲的量(Data normalization, a standardization of data processing, will be different units of variables, into dimensionless quantities)
- 2019-04-17 17:36:24下载
- 积分:1
-
fdtd_2D_TE_PML
fdtd的2d算法,pml边界条件,二维TE波(fdtd the 2d algorithm, pml boundary conditions, 2D TE wave)
- 2007-02-02 16:43:27下载
- 积分:1
-
gmm-4.2.tar
Generic templates of algorithms for sparse matrixs
- 2013-07-12 10:49:08下载
- 积分:1
-
Soct
假设有一个能装入总体积为T的背包和n件体积分别为w1 , w2 , … , wn 的物品,能否从n件物品中挑选若干件恰好装满背包,即使w1 +w2 + … + wn=T,要求找出所有满足上述条件的解。例如:当T=10,各件物品的体积{1,8,4,3,5,2}时,可找到下列4组解:(1,4,3,2),(1,4,5),(8,2),(3,5,2)。
[需求分析](Suppose there are a load of the backpack of the total volume of T and n volumes were w1, w2, ... wn items, whether selected from n items a number of exactly filled backpack, even if w1+w2+ ...+ wn = T, find out the solution of all the above conditions are met. For example: when T = 10, the volume of items {1,8,4,3,5,2}, can be found in the following four solutions: (1,4,3,2), (1,4,5 ), (8,2), (3,5,2). [Needs Analysis])
- 2012-06-14 16:25:10下载
- 积分:1
-
jaya
jaya algorithm source code
- 2017-03-01 16:24:24下载
- 积分:1