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123456
计算卡片过程密钥,加密密码数据,计算安全报文鉴别(MAC)过程密钥 (Calculating card key, the encrypted password data, calculate the safety message authentication (MAC) key)
- 2013-08-14 13:15:47下载
- 积分:1
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DIGSILETN-PF140.514--pojie-wenjian
PF140.514版digsilent软件的两个破解文件,按一定操作步骤即可免狗驱动,本人已在XP环境下使用,没有问题。希望对采用该软件的人有一点帮助!(Two crack file PF140.514 the version digsilent software, Free Dog certain steps to drive, I have XP environment, there is no problem. I hope the software a little help!)
- 2013-03-25 16:14:16下载
- 积分:1
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1111867176399d9765chaios
加密程序,很好用。亲自验证,完全正确。希望下载。(we can add and unadd a picture correctly.welcom to download.)
- 2012-05-17 12:06:01下载
- 积分:1
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md5encode
MD5加密算法,可以加密包含二进制数据的数据块,生成16字节MD5加密数据。(MD5 encryption algorithm to encrypt data blocks that contain binary data, generates a 16-byte MD5 encrypted data.)
- 2013-09-09 18:27:10下载
- 积分:1
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MUC1_C4
奇迹C1 C2 C3 C4协议加密与解密(MU C1 C2 C3 C4 encrypt and decrypt)
- 2021-02-17 12:19:46下载
- 积分:1
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373465435
基于VB的M5数学密码算法源码,有需要的就下载吧。(VB-based M5 mathematical algorithm source code, there is a need to download it.)
- 2013-08-13 23:07:29下载
- 积分:1
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AES
AES-rijndael 算法的详细资料, 包括
AES加密算法中的SBox及其C语言实现.pdf
FIPS197(chs).pdf
FIPS197.pdf
nist.url
Rijndael.pdf
rijndael算法流程.swf
Rijndael算法深入的研究.doc
Rijndael算法优化技术研究.doc
公钥密码体制与有限域(2).pdf
一种基于伽罗瓦域的密码系统.pdf(AES-rijndael algorithm detailed information, including the AES encryption algorithm in C language and its SBox realize. PdfFIPS197 (chs). PdfFIPS197.pdfnist.urlRijndael.pdfrijndael flow algorithm. SwfRijndael-depth study of algorithms. DocRijndael algorithm optimization technology research. Doc public key cryptosystem over finite fields and (2). pdf Galois field based on the password system. pdf)
- 2008-05-06 17:17:00下载
- 积分:1
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daiti
基本古典密码设计——周期为3的多表代替密码的设计和实现(Basic classical cipher design)
- 2011-12-14 11:04:59下载
- 积分:1
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exponentiation-algorithm
快速取模指数算法,C++编写,下载即可编译运行,RSA算法里面需要用到的(Take the fast modular exponentiation algorithm, C++ to prepare, you can compile and run the download, the RSA algorithm which need)
- 2012-04-26 10:00:30下载
- 积分:1
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aes
本程序可以实现AES16,24,32位任意长度的密码与任意长度的明文的加密与解密,并附有一实例(This procedure can achieve the AES16 24,32 password of any length and any length of plaintext encryption and decryption, with an example)
- 2021-03-15 14:09:22下载
- 积分:1