Keeloq

该程序使用C++写的一个基于递归子程序算法的语法翻译器，是在vs2012环境下编写的，供大家参考和学习(The program uses C++ to write an algorithm based on recursive subroutine syntax interpreter is written in vs2012 environment, for your reference and learning)

题目：某个公司采用公用电话传递数据，数据是四位的整数，在传递过程中是加密的，加密规则如下： 　　　 每位数字都加上5,然后用和除以10的余数代替该数字，再将第一位和第四位交换，第二位和第三位交换。 1.程序分析： 2.程序源代码：(Topic: a company USES the public telephone relay data, data is four integers, in the relay in the process is encrypted, encryption rules are as follows: Each Numbers add 5, then use and divided by the number of 10 instead of a remnant, then the first and fourth exchange, the second and third exchange. 1. The program analysis: 2. The source code:)

说明：  获取硬盘物理序列号,用来对软件加密，vs2008工程。(HD number)

计算机专业毕业设计--RSA加密算法的实现与设计(Graduate design computer RSA encryption algorithm and design)

des经典加密算法，实现数据交互过程中的保密(des classical encryption algorithm, data confidentiality during the interaction)

自己写的域天加密狗VB使用小例子，32位的加密狗快速开发源代码(Write your own domain days dongle VB use a small example, 32 dongle rapid development of source code)

说明：  编制程序，将输入的一行字符以加密的形式输出，然后将其解密，解密的字符串序列与输入的正文相比较，吻合时输出解密的正文，否则解密失败。 加密时，将每个字符的ascii码依次反复加上“4962873”中的数字，并在32（‘’）~122（‘z’）之间作模运算。解密与加密的顺序相反。例如输入正文“the result of 3 and 2 is not 8” 结果为： (Programming, the input line character output in an encrypted form, and then decrypted, the decrypted text sequence of characters compared with the input, output to decrypt the body of the agreement, otherwise the decryption failed. Encryption, ascii code of each character in turn repeatedly with &quot 4962873&quot in the figures, and 32 (' ' )~ 122 (' z' ) as a model between the operations. Decryption and encryption in reverse order. For example, enter the text &quot the result of 3 and 2 is not 8&quot results:)

用VC6.0实现的，运用NTL大整数库实现RSA的加密和解密算法，具有较高的效率！(VC6.0 achieved by applying NTL large integer achieve RSA encryption and decryption algorithms, with high efficiency!)

C++ implementation for S26

说明：  AES加密算法的加密部分，128位加密算法实现(AES encryption algorithm the encryption part, 128-bit encryption algorithms)