red-tree

以太网首部的一个c语言程序，代码功能是对设备要传送的帧进行排队(Ethernet header c language program code function is queued frames to be transferred to the device)

说明：  进程死锁.资源分配图的绘制 建立所需数据结构；  使用题目21存成的资源分配图的文件作为输入；  编写资源分配图化简算法；  每化简一步，在屏幕上显示化简的当前结果；  最后给出结论，是否死锁，如思索给出死锁的进程及资源； (Process deadlock. Resource allocation mapping  establish the required data structures  Use title 21 deposit into resource allocation graph file as input  writing resource allocation map simplification algorithm  Each simplification step, on-screen display simplification of the current result  Finally, the conclusion of a deadlock, deadlock is given as thinking processes and resources )

说明：  数据结构：Huffman编码。哈夫曼编码是哈夫曼树的一个应用。哈夫曼编码应用广泛，如JPEG中就应用了哈夫曼编码。 哈夫曼树又称最优二叉树，是一种带权路径长度最短的二叉树。(Data structure: Huffman coding. Huffman coding is an application of the Huffman tree. Huffman coding is widely used, such as JPEG in the application of the Huffman coding. Huffman tree, also known as the best binary tree is a weighted shortest path length binary tree.)

描述：足球俱乐部包括球员、普通行政人员。球员有姓名、年龄、能力、年薪、转会费、进球总数、服役年限等重要参数；普通行政人员有姓名、年龄、能力、年薪等参数。你需要给相关管理机构开发一个管理程序，实现对众多足球俱乐部管理的基本功能。具体功能包括： a) 俱乐部的增删改查，俱乐部的属性包括名称、现金、其下人员； b) 可以对所有球员的各项属性进行简单搜索，支持输入多个条件，条件之间用&&连接，例如： i. “年龄不大于25且服役年限大于5年且进球数大于100的球员”，查询表达式：!(@age>25) && @experience>5 && @kick>100 c) 支持球员在不同俱乐部间的买卖，买卖需符合以下条件：作为买方的俱乐部的现金>=球员的转会费，交易完成后，卖方将得到转会费。 要求： d) 必须采用面向对象的方式，使用类组织数据结构，并注意类的继承关系； e) 在题目要求基础上可以自行扩展功能，提供扩实用扩展功能者适当加分（加分不超过5分）。 (Description: Football club including players, general administrative staff. Player name, age, ability, salary, transfer fee, total number of goals, service life and other important parameters ordinary administrative staff name, age, ability, salary and other parameters. You need to give the relevant management agencies to develop a management program to achieve the number of football club management s basic functions. Specific features include: a) the club CRUD, the name of the club s property, including cash, under which personnel b) all players can perform a simple search of the property, supports input multiple conditions with && connection between conditions, for example: i. "Age is not greater than 25 and greater than 5 years service life and goals more than 100 players," query expression:! (@ age> 25) && @ experience> 5 && @ kick> 100 c) Support the players traded between different clubs, the sale subject to the following conditions: As a buyer s club cash> = pl)

.h文件。c++中的复数类，能够直接完成基本四则运算，输入输出流，完成一定范围内的比较运算(. H file. c++ classes in the plural, to directly perform basic arithmetic, input and output streams, to complete a range of comparison operators)

通过c语言数组算法解决josephus问题，m个人围成一圈，从第一个小孩开始顺时针方向每数到第n个小孩时这个小孩离开，最后剩下的小孩是胜利者。求第几个小孩为胜利者(C language array algorithm to solve the Josephus problem, m individual circle, from the first child began to count clockwise every n children, the child left, and finally the remaining child is the winner. A few kids for victory)

里面有50例经典算法，其中包括水仙花素，兔子的繁殖等古典问题的求解(There are 50 cases of classic algorithms, including daffodils prime, rabbit breeding classical problem solving)

哈夫曼树，基本的数据结构，用来编码和解码、用数组作为存储结构实现，

利用栈完成算术表达式求值：从键盘或文件中输入算术表达式，计算其结果并显示。要求处理过程为：（1）转换为后缀表达式并输出；（2）对后缀表达式求值并输出。 输入的表达式中可以有整数、实数、括号，运算符包括+、-、*、/、#（代表单目负）。可以多次输入不同的表达式进行计算，直到用户选择“退出”。栈的基本操作可以自己实现，也可以使用系统提供的STL实现。 (Done using an arithmetic expression evaluation stack: file input from the keyboard or an arithmetic expression, calculate and display the results. Requirements process: (1) to postfix expression and output (2) evaluation of the postfix expression and output. Enter the expression can be integers, real numbers, parentheses, operators including+,-,*,/,#( representatives unary minus). You can enter several different expressions are evaluated until the user selects " Exit." Stack can implement the basic operations, you can also use the system implementation of the STL.)

说明：  nuaa1108 多少连续的1 解题报告(Problem solving report )