matlabman-v5.2

实现FIR滤波器设计，执行代码可以进行FIR滤波功能。(FIR frighting desgion.)

一维水质模型，本程序研究一维河流的污染物扩散，短时间持续排放BOD的浓度变化规律 本程序采用中心隐式差分求解 问题t=0到t=1h偶然排放BOD 使河水断面L0=10mg/L河流平均速度5km/h 纵向弥散系数D=2km2/h BOD衰减系数k1=0.015h-1 解BOD浓度 L(x，t)(One-dimensional water quality model, the procedure of one-dimensional dispersion of pollutants in the river, a short continuous changes of the concentration of BOD emissions of the program implicit difference method with central issues t = 0 t = 1h accidental emissions to the BOD to the river section L0 = 10mg/L average speed of the river 5km/h vertical diffusion coefficient D = 2km2/h BOD decay coefficient k1 = 0.015h-1 Solution for BOD concentration L (x, t))

频率估计中的music算法的matlab实现(Frequency estimation algorithm in the matlab implementation of music)

cs mod current in boost cover.

开关电源buck的MATLAB的simulation仿真(Simulation of MATLAB simulation of switching power supply buck)

高分辨率雷达 距离向压缩算法滤波器设计 三种方法 全面设计(clc clear all close all 2013年9月28日 ---------------参数---------- Tr=42e-6 fs=9.5e6 K=0.7e11 Nfft=2048 -------------匹配滤波 时域生成-------------- t=(-Tr/2+1/fs:1/fs:Tr/2-1/fs) w = kaiser(length(t),2.5) w=w w = ones(1,length(t)) ht1=w.*exp(-1i*pi*K*t.^2) ht2=w.*exp(1i*pi*K*t.^2) hf1=fft(ht1,Nfft) hf2=fft(ht2,Nfft) figure subplot(211) plot(abs(hf1)) title( 匹配滤波器1 幅频响应 ) subplot(212) plot(phase(hf1)) title( 匹配滤波器1 相位 ) figure subplot(211) plot(abs(hf2)) title( 匹配滤波器2 幅频响应 ) )

四元数傅里叶变换代码，四元数在图像上的应用(quaternion fourier transform)

5/10/15/20阶的语音信号LPC 预测及其功率谱，并绘制误差函数图像(5/10/15/20 LPC prediction order of the voice signal and the power spectrum, and the mapping of the image error function)

说明：  最小二乘法汇总及matlab仿真的相关程序设计(Simulation of the least square method summary and the relevant programming matlab)

本程序中得到的收端OFDM信号的频谱波形，是与其发端信号的排步有关的。在发端的 ％ 载波安排上，128个载波有前后各32个载波是null载波(如果这前后各32各载波是带外频段， ％ 那么理论上它们都应该是零！)，中间的64个载波是数据载波。这样的排步很明显就是一个 ％ 两边低，中间高的频谱形式。所以，收端也应该是这个轮廓。 (this process the resumption end of the spectrum OFDM signal waveform, with the originator of the signal further on the row. The originator% carrier arrangements, 128 of the carrier after a 32 carrier is null carrier (if it was around the 32 is the carrier frequency band. % then theoretically they should be zero!) the middle 64 carrier data carrier. This arrangement is obviously further 1% lower on both sides, in the middle of the spectrum form high. Therefore, the admission should end this profile.)