face_detection

Finally, probability analysis, based on the chosen database, is performed and judgment whether the person is recognized is pronounced. Two different modeling techniques can be suggested for purposes of person identification or verification. The approach based on Hidden Markov Speaker Models (HMMs) with the mixtures of Gaussian distribution is text-dependent one. For this technology a speaker is described by a set of HMMs, constructing the set of speech groups spoken by that person. The speech groups may be phonemes or words [7]. The text-independent technology is rested upon Gaussian Mixture Speaker Models. For this technology each speaker is defined by only one model describing all utterances of that person. Identification in the range of both approaches is executed by evaluation of maximum a posteriori probability [7].

projected coordinate systems

利用MATLAB仿真小斜视角情况下理想点目标的合成孔径雷达回波数据，并利用RDA算法进行点目标成像。(the echo data of the ideal point target from small oblique Angle is simulated, and the target image is obtained by using RDA.)

说明：  脉冲控制多智能体一致性论文和实例仿真仿真(Pulse Control Multi-Agent Consistency Paper + Simulation)

这是一套完整的求解连铸二冷区喷嘴模拟试验传热系数的程序(This is a complete solution Caster two district cooling nozzle heat transfer coefficient simulation test procedures)

。本指南主要考虑的是代码（格式）的正确性、清晰性与通用性。本指南的 目的在于帮助写出更可能正确、易于理解、更具有共享性与更利于维护的代码。(. The main consideration in this Guide is the code (format) the accuracy, clarity and versatility. The purpose of this guide is to help write more likely to correct, easy to understand, to share more and more conducive to maintaining the code.)

matlab最基本的卡尔曼滤波的算法，最最基本的，就5步5句话，可以任意移植(matlab basic Kalman filter algorithm, the most basic, step 5 of the fifth sentence, can be transplanted)

利用matlab计算图像的辐射精度（包含均值、方差、偏斜度和陡度）和信息量。(Calculation of the radiation image using matlab precision (including mean, variance, skewness and steepness), and the amount of information.)

创建一个first order 低通模拟信号滤波器。输入为热噪音(creative a first order low pass filter, the in put is the white noise.)

猴子摘桃海滩上有一堆桃子，五只猴子来分。第一只猴子把这堆桃子凭据分为五份，多了一个，这只 猴子把多的一个扔入海中，拿走了一份。第二只猴子把剩下的桃子又平均分成五份，又多了 一个，它同样把多的一个扔入海中，拿走了一份，第三、第四、第五只猴子都是这样做的， 问海滩上原来最少有多少个桃子？(Peach Monkeys on the beach there is a pile of peaches, five monkeys for points. The first monkey peach credentials this heap is divided into five copies, more than one, the monkey to more than one thrown into the sea, took a. The second monkey the rest of the peaches and what the average is divided into five, and there are one, and it is likewise more than one thrown into the sea, took a third, fourth, fifth monkeys are actually doing that , the question on the beach for at least the number of the original peach?)