Optimizing-the-Normalized-Dead-Time_2

Web Corpus extends Multi Source Corpus Source Code for Andriod.

说明：  更新银行系统（BankSystem），模拟实现3个用户对统一账号进行存入、取出、转账等操作 CustomerGenerator线程：随机生成办理业务的顾客以及其操作类型、金额等 Cashier线程：从等待队列中抽取第一个顾客并为其办理业务 多线程：ArrayBlockingQueue<Customer>数组阻塞队列 文件列表： BankSystem.java Cashier.java Customer.java CustomerGenerator.java CustomerLine.java(BankSystem ArrayBlockingQueue<Customer>)

编写一个复数类，可以进行复数加法和减法运算。编写一个包含main方法的类（应用程序）测试该复数类。要求该复数类至少包含一个无参的构造方法和一个带参的构造方法；数据成员包括复数的实部和虚部，为double类型；包括两个方法，分别实现复数的加法和减法运算。(Write a complex class, which can add and subtract complex numbers. Write a class (application) containing the main method to test the complex class. The complex class is required to include at least one parametric construction method and one parametric construction method; the data members include the real and imaginary parts of the complex, which are of double type; and two methods are included to realize the addition and subtraction operations of the complex respectively.)

可用作java课程设计，具有万年历功能的日历，拥有记事本的功能(Used as a java course design, with calendar function calendar with notepad function)

测试servicemix的jbi标准组件(test servicemix the jbi standard components)

java开发的国家电力系统所有源代码 java开发的国家电力系统所有源代码java开发的国家电力系统所有源代码(java development of the national electricity system all the source code)

电子地图的简单实现，可以提供给初学者参考(Simple implementation of the electronic map, reference can be provided to beginners)

ssd3全部答案，西工大学生权威上传，无须担心答案是否正确。(ssd3 all the answers, NPU students the authority to upload, do not worry about the answer is correct.)

storm+kafka应用案例

说明：  实现扑克牌，一副牌中抽去大小王剩下52张（如果初练也可只用1～10这40张牌)，任意抽取4张牌（称牌组)，用加、减、乘、除（可加括号)把牌面上的数算成24。每张牌必须用一次且只能用一次，如抽出的牌是3、8、8、9，那么算式为（9-8)×8×3或3×8+（9-8)或（9- 8÷8)×3等。(In order to realize playing cards, 52 cards are removed from a deck (only 40 cards can be used for the first practice). Four cards are randomly selected (called card groups). The number on the deck is calculated as 24 by adding, subtracting, multiplying and dividing (brackets can be added). Each card must be used once and only once. If the drawn card is 3, 8, 8, 9, the formula is (9-8)*8*3 or 3*8+ (9-8) or (9-8 8)*3)