vc-and-matlab

八木天线有源折合振子馈电的新结构 (The new structure Yagi antenna active equivalent oscillator fed)

Complete Parallel Port Development. Covers all PP standards.

本代码可以实现绕过win7UAC（用户账户控制），可以很好的实现(This code can realize to bypass win7UAC, (User Account Control), can achieve a good)

在一个圆柱体上用二维棉片来模拟树皮表面的粗糙效果(cylinder in a two-dimensional cotton used to simulate bark film surface roughness effects)

实现MATLAB下的音频AGC，，关键是要有高效的算法。效果不错。 (Audio AGC on MATLAB, the key is to have efficient algorithms. Good results.)

基于嵌入式GUI的设计源码，在windows上开发(based on vc6.0, the GUI of embeded OS)

数字图像处理中的边缘检测程序合集，包括VC++和MATLAB实现(Digital Image Processing Edge Detection Collection procedures, including the VC and MATLAB)

dem模型读写(read dem)

使用的硬件EM1206，POP通信。可以以pop的邮箱通信方式发送邮件(The hardware used the EM1206, POP communication. You can send a message to pop mailbox communication)

说明：  给定n种物品和一个背包,物品i的重量是Wi,价值是vi,被包容量是C,应该如何选择装入被包的物品,使得装入背包中物品的总价值最大?对于每种物品i,只有两种选择,装入或者不装入. 输入:第一行两个正整数n(物品数)和C(容量) 第二行n个正整数n,表示物品价值 第三行n个正整数n,表示物品重量 输出:第一行表示总价值 第二行n个数(0/1),0表示物品不装入,1表示装入 例如, 输入: 5 10 6 3 5 4 6 2 2 6 5 4 输出 15 1 1 0 0 1 (Species of a given n items and a backpack, the weight of item i is Wi, the value of vi, was packet capacity is C, should be how to choose a package of items to be loaded, the backpack load in the largest total value of goods? For each item i, there are only two options, loaded or not loaded. Input: the first line of the two positive integer n (the number of items) and C (capacity) of the second line of n positive integer n, that the value of the third line of n positive integer n, that the weight of output: the total value of the first line of the second line, said n number of (0/1), 0 that the items do not load, that load 1 for example, enter: 5,106,354,622 6 5 4 output 15 1 1 0 0 1)