matlab-simulink

MatlabGUI的学习材料，是GUI编程的例程，配合视频10分钟学会GUI。(MATLAB GUI)

传统的解相干方法主要有空间平滑和子空间拟合两类,但这些方法或者阵列利用率低或者计算复杂度高,因此寻求计算量小且阵列利用率高的解相干测向方法有重要意义.该文基于前后向矢量重构理论,(The traditional decoherence methods spatial smoothing and subspace fitting into two categories, but these methods or array utilization rate is low or high computational complexity and therefore seek small amount of calculation and array of high utilization coherent finding method is important. This paper is based on the vector before and after Reconstruction,)

对实测获取的风压数据进行处理，评估风压分布的概率特性。(Evaluation of measured to obtain the wind pressure of data processing, the probability of wind pressure distribution characteristics.)

有源滤波器控制的一个example，供大家参考学习(Active filter control of a example, for your reference learning)

matlab实现landmarc定位算法的仿真(landmarc positioning algorithm （matlab）)

说明：  与常规的单目标遗传算法求解不同，该算法考虑两个目标函数的遗传算法(Different from the conventional single objective genetic algorithm, this algorithm considers the genetic algorithm of two objective functions)

线泰勒权的权值产生程序，可作为子函数调用。用于产生低旁瓣的差波束。用于阵列信号处理(line taylor vector, can be applied as sub function. difference beamforming.)

掺5 MgO的PPLN晶体温度调谐曲线，泵浦光1064nm，周期为29.5,30,30.5,31,31.5um(5 MgO doped PPLN crystal temperature tuning curve of the pump laser 1064nm, period 29.5,30,30.5,31,31.5um)

this matlab model describes harmonics generation for study very useful

一道程序编译顺序的考题，涉及到函数调用的先后顺序及运算符号的优先级等问题。下面我展开给你讲。 C的程序编译总是从main函数开始的，这道题的重点在“fun（（int）fun（a+c,b）,a-c）） ”语句。 系统首先要确定最外层 fun()函数的实参，第一个参数的确定需要递归调用fun()函数（不妨称其为内层函数）。内层函数的两个参数分别为x=a+b=2+8=10、y=b=5,执行函数体x+y=10+5=15,于是得外层函数的参数x=15。其另一个参数y=a-c=2-b=-6,再次执行函数体,得最终返回值x+y=15+(-6)=9。 (Compiling together the sequence of test procedures, involving the sequence of function calls and operator symbols, such as the priority problem. Now I give you to start speaking. Procedures for C compiler always start from the main function and at这道题the focus of " fun ((int) fun (a+ c, b), ac)) " statement. System must first determine the most outer layer of fun () function of real parameters, the first parameters of recursive calls required fun () function (may be called the inner function). Inner function separately for the two parameters x = a+ b = 2+8 = 10, y = b = 5, to execute the function body x+ y = 10+5 = 15, then the outer function parameters were x = 15 . Its another parameter y = ac = 2-b =- 6, once again to execute the function body may eventually return the value of x+ y = 15+ (-6) = 9.)