ALGraph

给定n种物品和一背包。物品i的重量是wi>0,价值为vi>0,背包的容量为c。选择装入背包的物品，使得装入背包中物品的总价值最大。(Given n kinds of goods and a backpack. Weight of the item i is wi> 0, the value of vi> 0, knapsack capacity c. Select the items into the backpack, so into the backpack of items in the total value of the maximum.)

基于MFC平台，实现多功能计算器，可求解复杂表达式，主要实现为数据结构中链表和数组，对于要熟悉链表和数组的初学者有很帮助。(Based on the MFC platform, to achieve multi-function calculator, can solve complex expressions, the main realization of the data structure for the list and array, to be familiar with the list and the array of beginners helpful.)

说明：  进程死锁.资源分配图的绘制 建立所需数据结构；  使用题目21存成的资源分配图的文件作为输入；  编写资源分配图化简算法；  每化简一步，在屏幕上显示化简的当前结果；  最后给出结论，是否死锁，如思索给出死锁的进程及资源； (Process deadlock. Resource allocation mapping  establish the required data structures  Use title 21 deposit into resource allocation graph file as input  writing resource allocation map simplification algorithm  Each simplification step, on-screen display simplification of the current result  Finally, the conclusion of a deadlock, deadlock is given as thinking processes and resources )

已知二叉树的先序遍历结果，建立二叉树并输出其先序、中序、后序遍历结果(Build a binary tree and print the results of preorder, midorder and postorder traversals based on the known result of preorder traversal)

Polynomial基于数据结构的思想,文件比较小,可以直接运行(Polynomial based on the idea of ​ ​ data structures, file is relatively small and can be run directly)

先序创建二叉树，将二叉树所有节点的左右子树交换，再先序遍历输出(create a binary tree in first order, exchange all the nodes of the binary subtree , then preorder output)

中国大学MOOC-陈越、何钦铭-数据结构 解题报告—06-3 六度空间 (Chinese University MOOC- Chen Yue, He Qinming- data structure Solving report of the problem- 06-3 Six degrees space)

数据结构中插入排序，堆栈排序等的用法还有希尔排序(Data structure insertion sort, stack, sort, etc. use well sorted Hill)

背包算法的c++简单实现，很有用的，可以看看(Knapsack algorithm)

用于迷宫问题的解决用户根据根据要求进行设置即可在屏幕上显示(Maze problems for users in accordance with the requirements set can be displayed on the screen)