qiongju

效验算法单循环链表，这些都是实用经典的算法和数据结构(Well-tested algorithm round robin list, these are practical classic algorithms and data structures)

c++ data struct stack

用控制台实现了经典的数据结构B树，可以通过测试文件.txt加载已有的B树，有插入，删除，查找的功能，加深对数据结构的理解。(Using the console to achieve the classic B tree data structure, you can pass the test document. Txt already loaded B-tree, there are insert, delete, search functions, to deepen understanding of the data structure.)

说明：  贪婪算法的简单描述 不过没做完 只是想下个程序 用用。。。。 (greed math)

说明：  由C程序实现的 数学上 滑雪问题 的代码实现，供大家学习用(Ski problem code for all to learn to use)

从屏幕输入字符 判断括号匹配问题 数据结构作业(Judgment parenthesis matching data structure operations input characters from the screen)

单向链表的创建与操作 设单向链表中节点的数据域的数据类型为整型，编写函数实现以下操作： （1）实现单向链表的创建（包括初始化）与输出操作，节点的个数及节点的数据由用户输入。 （源代码：ds3-1.c） （2）查找给定的单链表中的第i个节点，并将其地址返回。若不存在第i个节点，则返回空地址。 （源代码：ds3-2.c） （3）查找给定的单链表中值为n的节点，并将其地址返回。若不存在值为n的节点，则返回空地址。同时，还应通过参数传回该节点的序号。 （源代码：ds3-3.c） （4）删除给定的单链表中的第i个节点，成功返回1，失败返回0。 （源代码：ds3-4.c） （5）删除给定的单链表中值为n的节点，成功返回1，失败返回0。 （源代码：ds3-5.c） （6）在给定的单链表的第i位上插入值为n的节点。 （源代码：ds3-6.c） （7）在给定单链表的值为m的节点的前面插入一个值为n的节点。 （源代码：ds3-7.c） (Creation and operation of a one-way linked list Set up a one-way linked list data type node integer data fields , write a function to achieve the following: ( 1 ) achieve the creation of a one-way linked list ( including initialization ) and output operation , the number of nodes and node data entered by the user . ( Source : ds3-1.c) ( 2 ) Find a single list given in the i-th node and returns its address . Without the presence of the i-th node , returns an empty address. ( Source : ds3-2.c) ( 3 ) Find a given node in a given value of n single list , and return address . Without the presence of the value of n nodes , returns an empty address. Meanwhile, the number should be returned by the parameters of the node . ( Source : ds3-3.c) ( 4 ) Delete the given singly linked list in the i-th node , the successful return 1, else return 0 . ( Source : ds3-4.c) ( 5 ) to delete a single node in the list is given n , the successful return 1, else return 0 . ( Source : ds3-5.c) ( 6 ) )

使用三叉链表实现的哈夫曼树,统计inputfile1.txt中各字符的出现频率，并据此构造Huffman树，编制Huffman 码；根据已经得到的编码，对01形式的编码段进行译码。 具体的要求： 1．将给定字符文件编码，生成编码，输出每个字符出现的次数和编码； 2．将给定编码文件译码，生成字符，输出编码及其对应字符。 (Emergence of the frequency of each character in the trigeminal lists using the Huffman tree, statistics inputfile1.txt, and accordingly the Huffman tree structure, preparation of Huffman code according to the coding has been. 01 to form the code segment for decoding. Specific requirements: 1 coding the given character file, generating the encoding, and outputting the number and encoding of each character 2 will be given the encoding file decoding, generating the character, the output code and its corresponding character.)

实现超市中排队购物用时最短，是计算机算法设计与分析中的一道题。自己写的程序，原创！(Achieve queued supermarket shopping with the shortest, is a question in the design and analysis of computer algorithms. Write their own procedures, original!)

分析汉诺塔，选择合适方法编程实现汉诺塔问题的解答。(Analysis of the Tower of Hanoi, select the appropriate method of programming the answers of the Tower of Hanoi problem.)