66FFma

国际组织OMA的资料。OMA是有运营商组织的一个国际形的组织，更多的是从运营角度提供一些标准规范。(international organizations OMA information. OMA is the operator of a form of international organizations, more of the operation from the perspective of some standards and norms.)

in system programing programator 89isp

kk飞控的程序，kk飞控是一款低端的很廉价的很好的飞控程序。适合初学者玩多轴飞行器。(kk flight control procedures, kk flight control is a very cheap low-end good fly control program. Suitable for beginners to play multi-axis aircraft.)

通信信号处理丛书，全面系统地阐述了信号处理的的基本理论与应用，是每个通信人的必备参考资料。 (Communication Signal Processing Series, a comprehensive and systematic exposition of the basic signal processing theory and applications, is an essential reference for each communication.)

algorithm recursive a generating inverted number in c language

聚类分析在入侵检测中的应用研究，09最新论文，从CNKI上买来的，希望对大家有用。(Cluster Analysis in Intrusion Detection Research, 09 latest papers, bought from CNKI on, we want to be useful.)

program that will calculate how many odd integers in a given interval from 1 to N, where N is entered through the keyboard. The program will print out the total number of odd numbers in a given interval as the product of all odd numbers in that interval. As a result, the program should print "at intervals of 1 to N has <x> odd numbers and their product is <proizvod>.".

FLKT是C++之父写的教材中用到的GUI库。(FLTK (pronounced "fulltick") is a cross-platform C++ GUI toolkit for UNIX® /Linux® (X11), Microsoft® Windows® , and MacOS® X. FLTK provides modern GUI functionality without the bloat and supports 3D graphics via OpenGL® and its built-in GLUT emulation. FLTK is designed to be small and modular enough to be statically linked, but works fine as a shared library. FLTK also includes an excellent UI builder called FLUID that can be used to create applications in minutes. FLTK is provided under the terms of the GNU Library Public License, Version 2 with exceptions that allow for static linking. )

矩阵转换四元数代码 欧拉角转换四元数代码 四元数转换到矩阵代码(The quaternion matrix transformation code Euler angles conversion quaternion code converts quaternion to a matrix code)

用数组的方式求鞍点。开始时假设a[i][0]最大，将列号0赋给maxj保存，找出第i行中的最大者。。(With an array of ways for saddle point )