登录
首页 » matlab » ricianchannel

ricianchannel

于 2013-02-28 发布 文件大小:1KB
0 225
下载积分: 1 下载次数: 25

代码说明:

   Each trial uses 10000 bits is used for DQPSKModulator in Rician channel with K-factor value is 3

下载说明:请别用迅雷下载,失败请重下,重下不扣分!

发表评论

0 个回复

  • Flow-calculation
    简单经典的潮流计算程序 适合初学者理清潮流计算的编程思路(Simple classic flow calculation procedures, suitable for beginners to sort out programming ideas flow calculation)
    2013-08-22 22:03:14下载
    积分:1
  • MATLAB-demystify
    说明:  我的matlab学习就是从本书开始,他适合初学者,可以快速带你进入matlab应用(My study is from the book to start matlab, he suitable for beginners, you can quickly take you into the matlab application)
    2011-03-26 07:33:49下载
    积分:1
  • tag_Big_image
    tag big data in matlab
    2013-01-14 13:58:53下载
    积分:1
  • lssvm
    最小二乘支持向量机二分类问题实例程序,了解最小二乘支持向量机的编程方法,数据方式(lssvm classification)
    2013-09-29 10:48:12下载
    积分:1
  • CBM
    根据切比雪夫近似得到的计算简正波的程序,能够较精确获得本地简正波(A Matlab code for computing normal modes based on Chebyshev approximations )
    2013-12-09 16:00:19下载
    积分:1
  • hafuman
    哈弗曼编码用MATLAB语言和C语言来解释(Huffman coding using MATLAB and C language to explain)
    2013-11-13 09:17:36下载
    积分:1
  • jacob4
    matlab function to calculate jacobian matrix fou a quadrilateral element
    2013-08-15 02:11:32下载
    积分:1
  • 0470723173
    Cellular Authentication for Mobile and Internet Services introduces the reader into the field of secure communication for mobile applications, including secure web browsing with a phone or PC, Single Sign-On (SSO), mobile broadcast content protection, secure location services, etc. The book discusses the Generic Authentication Architecture (GAA) of the mobile standardization body 3rd Generation Partnership Project (3GPP) and its American counterpart 3GPP2 in full detail and with all variants. It explains the usage of GAA by various standardization bodies and standardized applications, and also looks at a number of non-standardized ones, such as secure remote login to enterprise environment and card personalization.
    2010-08-16 17:57:46下载
    积分:1
  • 3
    说明:  求三角对角方程组Tx=f的解,其中T=[1 1 0 0 0,1 2 1 0 0,1 1 3 1 0,0 0 1 4 1, 0 0 0 1 5],x =[x1,x2,x3,...x5],f=[3,8,15,24,29](Diagonal triangle demand equations Tx = f the solution, in which T = [1 1 0 0 0,1 2 1 0 0,1 1 3 1 0,0 0 1 4 1, 0 0 0 1 5], x = [ x1, x2, x3, ... x5], f = [3,8,15,24,29])
    2010-08-26 21:09:57下载
    积分:1
  • simulink
    关于2FSK在高斯和瑞利信道的传输,以及OFDM系统的仿真模型,还有QPSK的Simulink仿真。(About 2FSK in Gaussian and Rayleigh channel transmission, as well as the OFDM system simulation model, as well as QPSK the Simulink simulation.)
    2008-06-05 13:43:48下载
    积分:1
  • 696516资源总数
  • 106914会员总数
  • 0今日下载