proposed_method

哈夫曼编码解码器，在matlab环境下实现的编码解码，希望对大家有用(Huffman codec in matlab environment to achieve the encoding and decoding, we hope to be useful)

在matlab上读取数据 应用广泛 便于以后对数据进行进一步的处理 (Input the data by matlab)

对于OFDM初学者很有帮助，是很好的学习程序哦，可以学会用matlab仿真(the study of )

全局阈值程序，用于matlab中图像分割，能够对比强烈的图片进行较好的分割。(Global threshold program, used in matlab image segmentation, can be used to better segmentation contrast images. )

A set of C++ and Matlab routines implementing the surfacelet transform

学习向量量化神经网络模型与学习算法及MATLAB实现(Learning vector quantization neural network model and learning algorithm)

C++ Graphics Class Library for MS Windows

某市有一码头，每次仅容一辆船停泊装卸货，由于经常有船等候进港，部分人提出要扩建码头。经过调查历史资料发现，码头平均每月停船24艘，每艘船的停泊时间为24±20小时，相邻两艘船的到达时间间隔为30±15小时，如果一艘船因有船在港而等候1小时，其消耗成本为1000元。经预算，扩建码头大约需要1350万元，故市长决策如下：如果未来五年内停泊船只因等候的成本消耗总和超过扩建码头花费则扩建码头，否则，不予扩建。因此，希望你能够帮助市长做出决策。此问题已知到达的大概时间和大概停泊时间，对于此问题用概率统计的方法来做比较复杂，可用程序随机产生到达时间和停泊时间来模拟未来五年内船的停泊，多次模拟预测停泊情况，以做出决策(。-Problem in a city with a terminal expansion dock, each only allow a boat moored loading and unloading, as often there are waiting boat into port, some people proposed to expand pier. Terminal stopping 24 per month, per vessel berthing time of 24 ± 20 hours, the arrival of two adjacent vessels interval 30 ± 15 hours, if a ship due to boat in the harbor while waiting for one hour, and its consumption cost of 1,000 yuan. The budget of about 13.5 million yuan expansion dock, so the mayor decision as follows: If a ship is moored next five years, the cost of waiting more than the sum of consumption spending is expanding marina pier extension, otherwise, not expanded.)

说明：  支持向量机的C++源代码包，用机器学习的方法处理优化问题，可以作为matlab的工具箱。(C++ code for proceeding SVM problems！)

关于自振动仿真的源代码，可以看看，第一传求关注，支持。(Source Courseware)