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基于MatLab和VC编写程序，实现点云数据的快速建模，三角网格的绘制。(MatLab, and VC-based programming to achieve fast data point cloud modeling, triangular mesh rendering.)

Matlab数字图像处理源代码，里面有书上的代码，便于读者下载(Matlab Digital image processing source code，There are books code, convenient for readers to download。)

说明：  C+陷阱与缺陷,适合于各个阶段的学习者学习!(C+ traps and defects, suitable for all phases of learners!)

LEACH的源代码，详细注释，适合初学WSN路由协议的同学学习。(LEACH source code, detailed notes, WSN routing protocols suitable for novice students to learn.)

gsl具有强大的矩阵运算，信号分析功能，使用gsl提供的库文件能加速vc开发复杂的数学运算，摆脱对MATLAB的依赖(gsl own powerful function of matrix operations and signal analysis , use the gsl provided library files,you can speed up the development of complex mathematical operations vc, get rid of dependence on the MATLAB)

抽象类以及纯虚函数的相关笔记。Figure作为基类，派生出Circle，Square(Abstract classes and pure virtual functions related notes. Figure as a base class, derived Circle, Square)

主要是HDB3编程一些资料，内含一个MATLAB实现HDB3的实验报告(The main program is HDB3 some information, containing a MATLAB implementation HDB3 lab reports)

MATLAB混合编程课程设计资料（VC，VB） 在Matlab环境下实现混合编程的学习者可以下载(MATLAB hybrid programming curriculum design information (VC, VB) in the Matlab environment to achieve mixed programming learners can be downloaded.)

一道程序编译顺序的考题，涉及到函数调用的先后顺序及运算符号的优先级等问题。下面我展开给你讲。 C的程序编译总是从main函数开始的，这道题的重点在“fun（（int）fun（a+c,b）,a-c）） ”语句。 系统首先要确定最外层 fun()函数的实参，第一个参数的确定需要递归调用fun()函数（不妨称其为内层函数）。内层函数的两个参数分别为x=a+b=2+8=10、y=b=5,执行函数体x+y=10+5=15,于是得外层函数的参数x=15。其另一个参数y=a-c=2-b=-6,再次执行函数体,得最终返回值x+y=15+(-6)=9。 (Compiling together the sequence of test procedures, involving the sequence of function calls and operator symbols, such as the priority problem. Now I give you to start speaking. Procedures for C compiler always start from the main function and at这道题the focus of " fun ((int) fun (a+ c, b), ac)) " statement. System must first determine the most outer layer of fun () function of real parameters, the first parameters of recursive calls required fun () function (may be called the inner function). Inner function separately for the two parameters x = a+ b = 2+8 = 10, y = b = 5, to execute the function body x+ y = 10+5 = 15, then the outer function parameters were x = 15 . Its another parameter y = ac = 2-b =- 6, once again to execute the function body may eventually return the value of x+ y = 15+ (-6) = 9.)

MATLAB5.X入门与提高.pdf 想学习MATLAB编程的入门书籍，可以参考(Introduction and improvement of MATLAB5.X PDF want to learn MATLAB programming entry books, can refer to )