登录
首页 » matlab » analysis

analysis

于 2011-09-15 发布 文件大小:576KB
0 262
下载积分: 1 下载次数: 14

代码说明:

  用matlab实现对语音信号的短时分析,包括清音和浊音的判决,基音周期的估计,实验报告。(use matlab language analysis the speech signal,contains the analysis for unvoiced sound and voiecd sound.)

下载说明:请别用迅雷下载,失败请重下,重下不扣分!

发表评论

0 个回复

  • fsk1
    基于matlab的2fsk的调制与解调源程序,以及眼图,误码率的计算,相干解调,非相干解调的比较(Matlab-based 2fsk the source of the modulation and demodulation, as well as the eye diagram, bit error rate calculation, coherent demodulation, comparison of non-coherent demodulation)
    2009-05-02 16:45:31下载
    积分:1
  • ConvAndCorrDemo
    主要介绍如何实现卷积和相关的界面演示,并可以自己编写信号,操作方便。(Describes how to implement convolution and correlation of the interface presentation, and you can write your own signal, easy to operate.)
    2011-09-20 09:26:27下载
    积分:1
  • Battery1234FFRSStatus
    IT IS FOR BATTERY STAT UNKNOWN DEMO
    2014-10-30 11:44:20下载
    积分:1
  • 3898238942894zhiwen
    基于matlab的指纹库指纹识别设计,matlab源码和指纹库。(Matlab-based fingerprint identification fingerprint database design, matlab source code and fingerprint database.)
    2013-11-07 15:24:18下载
    积分:1
  • somp
    多频带信号压缩采样的回溯SOMP重构方法(Multi-band signal compression sampling back SOMP reconstruction)
    2013-04-28 22:23:20下载
    积分:1
  • GA2_LF~1
    genetic algorithms explained
    2015-04-16 17:54:10下载
    积分:1
  • dream
    超声场仿真工具包,matlab编写。请认真书写上传资料的详细功能、包含内容说明(FUCTION LIKE Field_II)
    2009-11-12 02:34:55下载
    积分:1
  • Inequality-constrained-optimization
    德克萨斯大学奥斯汀分校Baldick Ross教授关于不等式约束最优化问题的课件。详细阐述了最优潮流等典型最优化问题。(Baldick Ross Professor of the University of Texas at Austin courseware inequality constrained optimization problem. The typical elaborate OPF most optimization problems.)
    2020-11-17 20:09:39下载
    积分:1
  • SIMULINK
    matlab/simulink模块的详细使用说明(Detailed instructions for use matlab/simulink module)
    2015-03-30 10:09:53下载
    积分:1
  • Recursive_integer_division
    递归法求解整数划分。 整数划分,是指把一个正整数n写成如下形式: n=m1+m2+…+mi (其中mi为正整数,并且1 <= mi <= n),则{m1,m2,...,mi}为n的一个划分。 如果{m1,m2,...,mi}中的最大值不超过m,即max(m1,m2,...,mi)<=m,则称它属于n的一个m划分。这里我们记n的m划分的个数为f(n,m) (Recursive method integer division. Integer division, refers to a positive integer n written as follows: n = m1+m2+ ...+mi (where mi is a positive integer, and 1 < = mi < = n), then {m1, m2, ..., mi} is a division of n. If {m1, m2, ..., mi} does not exceed the maximum value of m, i.e., max (m1, m2, ..., mi) < = m, m n is said that it belongs to a division. Where m is the number of division n our mind is f (n, m) )
    2014-02-06 14:21:38下载
    积分:1
  • 696516资源总数
  • 106914会员总数
  • 0今日下载