opengl-ppt-part6_8

关于走迷宫算法的实现程序，完全采用C++语言实现，可以运行(Maze algorithm program, fully C++ language, you can run)

设计一系统，实现医药公司定期对销售各药品的记录进行统计，可按药品的编号、单价、销售量或销售额做出排名。(Design a system, the realization of pharmaceutical company on a regular basis to update a record of each drug sales statistics, according to the serial number of drugs, unit price, sales or sales rankings.)

自控应用svm的介绍文档，方便下载传看。(mysvm is used to train a SVM on a given example set and testing the results.it is very conveninent to learn about it by u self.)

at89c2051利用74ls164 驱动 共阳极数码管(74ls164 driver to use a total of at89c2051 digital tube anode)

产生GUID的源码，使用C++开发。并且包含了把32为GUID转换为16为可见字符的算法(GUID source, use C++ development. And contains 32 to a GUID algorithm 16 visible characters)

上传程序用于解析Novatel输出range 信息，解析结果已经验证。(The upload process is used to resolve the Novatel output range information, analytical results have been verified.)

QRCode font package can print QRCode barcode as a font, Win32 DLL encoder and .NET class library encoder are provided, the encoders are different for the trial version package and the full version package, the trial version encoders append "MW6 Demo" to the string encoded with QRCode.

说明：  距阵链乘问题: 找出矩阵链乘A(35*40) A(40*20) A(20*10) A(10*15)的最佳相乘次序。 算法来自:计算机算法导引(matrix chain by : identify matrix chain by A (35* 40) A (40* 20) A (20* 10) A (10* 15) concludes the best order. Algorithm from : computer algorithm Seeker)

设p是素数，a是p的本原根，即a1,a2,a3,…,ap-1在mod p下产生1到p-1的所有值，所以对任何b属于{1,…,p-1},有唯一的i属于{1,…,p-1}使得ai mod p 等于p。称i为模p下以a为底b的离散对数。(P is a prime number based, a is the primitive root p, that is, a1, a2, a3, ..., ap-1 in the mod p under 1 to p-1 for all values, so for any b belongs to (1, ..., p-1), there are only i belong to (1, ..., p-1) makes ai mod p equivalent to p. Said i was under the modulus p to a for b at the end of the discrete logarithm.)

人工智能算法包含各种情况可在Delphi和C++中使用(artificial intelligence algorithms encompass a variety of situations in Delphi and C use)