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5
一道程序编译顺序的考题,涉及到函数调用的先后顺序及运算符号的优先级等问题。下面我展开给你讲。
C的程序编译总是从main函数开始的,这道题的重点在“fun((int)fun(a+c,b),a-c)) ”语句。
系统首先要确定最外层 fun()函数的实参,第一个参数的确定需要递归调用fun()函数(不妨称其为内层函数)。内层函数的两个参数分别为x=a+b=2+8=10、y=b=5,执行函数体x+y=10+5=15,于是得外层函数的参数x=15。其另一个参数y=a-c=2-b=-6,再次执行函数体,得最终返回值x+y=15+(-6)=9。 (Compiling together the sequence of test procedures, involving the sequence of function calls and operator symbols, such as the priority problem. Now I give you to start speaking. Procedures for C compiler always start from the main function and at这道题the focus of " fun ((int) fun (a+ c, b), ac)) " statement. System must first determine the most outer layer of fun () function of real parameters, the first parameters of recursive calls required fun () function (may be called the inner function). Inner function separately for the two parameters x = a+ b = 2+8 = 10, y = b = 5, to execute the function body x+ y = 10+5 = 15, then the outer function parameters were x = 15 . Its another parameter y = ac = 2-b =- 6, once again to execute the function body may eventually return the value of x+ y = 15+ (-6) = 9.)
- 2009-03-15 15:36:23下载
- 积分:1
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CS-Channel-Estimation
信道估计程序,ieee发表的文章对应的原码,本人已经验证,可以使用。(Channel estimation procedures, ieee post corresponding to the original code, I have verified that you can use.)
- 2013-10-25 21:08:24下载
- 积分:1
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pca-cPP-svd-algorithm
主成分分析的c++实现使用奇异值分解svd算法(Principal Component Analysis based on svd algorithm ,used c++)
- 2012-11-22 15:18:38下载
- 积分:1
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222645116720055304472832
本文以数字图像处理、压缩技术和MATLAB应用为基础,偏重于MATLAB图像处理的分析和应用。涉及到关于图像处理的图像增强、二值处理、小波分析和图像压缩的基本概念,解决了利用低通、高通滤波,膨胀,腐蚀,平滑,边缘提取和基于DCT变换,小波变换的图像压缩技术的图像处理,制作了一个关于图像处理和图像压缩的系统。(good)
- 2009-04-24 00:37:04下载
- 积分:1
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UART_GUI
RS232通訊用GUI,可偵測PC上的所有Port供使用者選擇,並提供9600、115200兩個baud rate供使用者選擇(如需其他baud rate可自行於code內添加),提供RX、TX接收傳送功能,下方接收欄可接收第一個0x0A指令之前所有資料,右方接收欄則接收剩餘所有資料。(RS232 communication with the GUI, can be detected on all Port PC for users to choose and provide 9600,115200 two user selectable baud rate (for other baud rate can add their own in the code), to provide RX, TX reception transmission function, the receiver can receive all the information bar below before the first 0x0A command bar on the right to receive all the information you receive surplus.)
- 2014-12-22 17:51:39下载
- 积分:1
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OutputText
OutputText.rar例子,关于txt输出,注释的特别详细(OutputText,special for txt)
- 2013-12-10 10:14:33下载
- 积分:1
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pid_adrc_dtc_mc0
基于比例积分微分控制的永磁同步电机直接转矩控制仿真(Permanent Magnet Synchronous Motor Direct Torque Control Simulation of PID control)
- 2020-06-30 11:00:02下载
- 积分:1
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code
角点检测程序源码,使用的是HARRIS角点提取方法,效果很好。(Corner detection program source code, using extraction methods HARRIS corner, very good.)
- 2007-11-28 22:12:20下载
- 积分:1
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Recursive_integer_division
递归法求解整数划分。
整数划分,是指把一个正整数n写成如下形式:
n=m1+m2+…+mi (其中mi为正整数,并且1 <= mi <= n),则{m1,m2,...,mi}为n的一个划分。
如果{m1,m2,...,mi}中的最大值不超过m,即max(m1,m2,...,mi)<=m,则称它属于n的一个m划分。这里我们记n的m划分的个数为f(n,m) (Recursive method integer division. Integer division, refers to a positive integer n written as follows: n = m1+m2+ ...+mi (where mi is a positive integer, and 1 < = mi < = n), then {m1, m2, ..., mi} is a division of n. If {m1, m2, ..., mi} does not exceed the maximum value of m, i.e., max (m1, m2, ..., mi) < = m, m n is said that it belongs to a division. Where m is the number of division n our mind is f (n, m) )
- 2014-02-06 14:21:38下载
- 积分:1
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gal_tsp_src
searching for genetic algo in matlab for tsp
- 2013-08-07 16:54:45下载
- 积分:1