comparallel

in this project data is hiding by LSB stegnography the shifting opertor is used to shift the data

经验模态分解程序集，一类可以有效进行信号分段以及分析和处理的源代码。(Empirical mode decomposition procedure)

tHIS IS CODED EXAMPLE FOR RAILWAY MANAGEMENT SYSTEM

超松弛迭代法数值实验，matlab程序，含部分注释(Numerical experiments over relaxation iterative method, matlab program, including some comments)

说明：  gyro matlab fire source file

说明：  自编多尺度样本熵程序，实例中用于一段轴承故障数据，简单易懂。MultiscaleSampleEntropy函数中的SampleEntropy也可以单独拎出来计算单个样本熵。(Multi scale sample entropy is used for a section of bearing fault data, which is easy to understand. SampleEntropy in the MultiscaleSampleEntropy function can also be picked up separately to calculate the entropy of a single sample.)

简单暂态计算：输入初始功率、无限大系统母线电压、系统等值电抗矩阵、惯性时间常数、间断数、发生故障时段、每段间隔时间；得到结果有不平衡功率、功角增量、电磁功率、发电机转子摇摆曲线(Simple transient calculation: input initial power, infinite system bus voltage, the system equivalent reactance matrix, inertia time constant, continuous number, the failure time, each interval get results uneven power, power angle increment, electromagnetic power generator rotor swing curves)

拉格朗日算法已知三组温度与压力数据:(3,53.5) (4,55.3) (5,56.2)求4.15对应的值为55.492375，结果正确。如果将以上数组顺序颠倒，已知压力55.492375求对应的温度，结果为4.185739，可以看到上下两个结果误差较大，就是说不能象这样去颠倒顺序去求值的。但是实际上我们可能经常要求知道压力去求温度，那么遇到这样的情况，只能采用试算法：一种简单的方法就是二分法迭代，书上都有介绍就不多讲了。(Lagrange method已知三组温度与压力数据:(3,53.5) (4,55.3) (5,56.2)求4.15对应的值为55.492375，结果正确。如果将以上数组顺序颠倒，已知压力55.492375求对应的温度，结果为4.185739，可以看到上下两个结果误差较大，就是说不能象这样去颠倒顺序去求值的。但是实际上我们可能经常要求知道压力去求温度，那么遇到这样的情况，只能采用试算法：一种简单的方法就是二分法迭代，书上都有介绍就不多讲了。)

该算法是用Matlab语言编写的蚁群算法，可以有效的求解城市间的最短路径，并且能够动态的呈现求解过程。(The algorithm of Matlab language of ant colony algorithm, can effectively solve the shortest path between cities, dynamic and able to show the change process.)

说明：  本压缩包是对资料进行整合，整合内容均可用。包括快速emd eemd等资料(This compression package is for data integration, and the integrated content is available. Including fast EMD EEMD and other data)