-
CH5MATLAB
MATLAB经典示例
以示参考
十分有用(MATLAB classic example to show reference useful)
- 2013-02-25 09:15:44下载
- 积分:1
-
matlab
对信号进行时域特征提取,个人已使用,感觉很不错!(The time domain feature extraction of the signal, the individual has been used, I feel very good!)
- 2020-07-14 22:28:52下载
- 积分:1
-
ver_0.8
CNN - Convolutional neural network class
- 2010-06-13 23:09:47下载
- 积分:1
-
sjd
三节点平面应力单元有限元分析,计算出了其节点力、位移和应力。(Three-node plane stress element finite element analysis to calculate the strength of its nodes, displacement and stress.)
- 2010-05-20 23:47:25下载
- 积分:1
-
allsv_pwmnikhil
SVPWM technique converter..all types
- 2011-05-23 17:57:04下载
- 积分:1
-
IEEE34-with-wind
介绍关于IEEE34-with-wind及其仿真模型(About IEEE34-with-wind and its simulation model)
- 2013-10-01 19:23:05下载
- 积分:1
-
MATLAB123
Matlab studing materials
- 2010-01-23 13:49:23下载
- 积分:1
-
YTY_GA_Final
To find the largest fitness value and its location
寻找最大适应性及相应的位置!Population N=50;crossover bits=n/2 (half of bits of an individual) with random locations,mutation bits = 4 种群数 N=50,交换位数= n/2, 即个体位数的一半,且位置随机;
变异位数统一取为4;
Nc=20,28,36,44,individuals for crossover(交换的个数)。Nm=1,5,10,15, individuals for mutation(变异的个数)。(To find the largest fitness value and its location to find the location of the maximum adaptability and the corresponding! Population N = 50 crossover bits = n/2 (half of bits of an individual) with random locations, mutation bits = 4 population size N = 50, exchange digits = n/2, ie half of the median individual, and random position variation is taken as unity median 4 Nc = 20,28,36,44, individuals for crossover (exchange number). Nm = 1,5,10,15, individuals for mutation (the number of variations.))
- 2010-12-27 21:23:27下载
- 积分:1
-
SolveNonEq
求解非线性方程,二分法、牛顿法、割线法、steffensen法(For Solving Nonlinear Eq)
- 2013-11-29 22:50:13下载
- 积分:1
-
Project_Thesis_OFDM
Project thesis with included matlab codes of ICI Cancellation in OFDM systems.
- 2014-02-16 02:34:18下载
- 积分:1