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说明: 抽象类以及纯虚函数的相关笔记。Figure作为基类,派生出Circle,Square(Abstract classes and pure virtual functions related notes. Figure as a base class, derived Circle, Square)
- 2014-02-20 15:33:35下载
- 积分:1
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Matlab
信息熵 离散无记忆信道容量的迭代计算
Shannon编码 Fano编码 Huffman编码(Discrete information entropy of the iterative calculation of the memory channel capacity
Shannon coding Fano coding Huffman coding)
- 2012-03-27 20:02:45下载
- 积分:1
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camera_1
用matlab控制摄像头 对所采集的视频提取图片,再进行后续处理(Control using matlab camera captured video extract pictures, and then the subsequent processing)
- 2013-04-25 15:28:37下载
- 积分:1
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Ssimmple_jpegu
简易的JPEG压缩程序源码(MMatlab实现)
(Easy JPEG compression program source (MMatlab implementation))
- 2012-09-15 14:17:31下载
- 积分:1
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tsuspension_so
matlab 实现汽车悬架分析,四分之一、二分之之一,整车悬架悬架 ,经测试可直接使用。
(matlab vehicle suspension analysis, one-quarter, one-half of vehicle suspension suspension, tested directly use.)
- 2012-09-30 19:24:01下载
- 积分:1
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bWTBB_v33a
一种基于matlab/simulink的风力力发电建模系统,里面有非常多实用的模型能直接使用
(A wind power generation modeling system based on matlab/simulink, there are very practical model can be used directly)
- 2012-07-19 20:56:06下载
- 积分:1
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sfunctin
matlab/s函数的应用,有兴趣的读者可以一起交流。(matlab/s function of the application, interested readers can join the exchange.)
- 2007-09-29 18:47:37下载
- 积分:1
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ResearchingRelialiabilityoftheComplexNetworkSystem
在对复杂网络系统可靠性优化配置方法研究的基础上,编制出系统可靠度优化配置计算机程序.(in the complex network configuration system reliability optimization method on the basis of produce distribution system reliability optimization computer program.)
- 2007-02-26 16:35:11下载
- 积分:1
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psa
说明: 既可以用于高压输电网的潮流解算,又可以用于低压配电网的潮流解算,还可以同时解算输电网
加配电网的混合潮流问题,程序为PQ 分解法.(Both the trend for high-voltage transmission grid solver, but also the trend for low voltage distribution network solver, solver can also increase with the power transmission grid hybrid power flow problem, the program for the PQ decomposition.)
- 2011-04-07 14:26:13下载
- 积分:1
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surshrHEDA
基于直方图的分布估计算法matlab源程序,测试函数选用的是30维函数(for h=1:m
for j=1:((x2-x1)/binswidth)
if (x(h)>=x1+(j-1)*binswidth)&(x(h)<x1+j*binswidth)
H(j)=H(j)+1
end
end
end
[wid,len]=size(H)
H=H/(wid*len)
objvalue=sort(objvalue, descend )
for j=1:((x2-x1)/binswidth))
- 2013-03-15 10:44:15下载
- 积分:1