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mie散射软件
说明: 计算mie散射相关参数,根据颗粒粒径 ,入射光波长 ,颗粒折射率,介质折射率,计算不同角度下散射光强,不同粒径下的消光系数。(Calculate the mie scattering related parameters, calculate the scattered light intensity at different angles and the extinction coefficient at different particle sizes according to particle size, incident light wavelength, particle refractive index, and medium refractive index.)
- 2019-02-25 13:09:38下载
- 积分:1
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software-for--Astrodynamics
非常有用的卫星轨道参数计算模块,很方便进行轨道特性分析。(This is a very useful toolbox for satellite s trajectory parameter computation )
- 2014-02-18 13:47:24下载
- 积分:1
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VBANSYSMATLAB
介绍了一种基于VB 后台调用ANSYS和MATLAB进行设计计算的方法。通过借助VB设计的参数化输入界面,
调用APDL编写的模型分析程序和MATLAB编写的可靠性计算程序,实现了在用户界面上以可视化的形式显示计算结果功
能,并应用于铁路接触网设计的可靠性计算中,结果显示证明了计算软件的可行性和实用性。(Describes the background of a call based on ANSYS and MATLAB VB design calculation. VB by using the design parameters of input interface, called APDL model prepared by the procedures and the reliability of computer program written in MATLAB, implementation in the user interface to visualize the results in the form of display features, and design used in railway catenary the reliability of the calculation, the results proved the feasibility and practicality of computing software.)
- 2010-07-07 09:28:07下载
- 积分:1
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raoguosuoyouyonghudecengHOOK
A、分析API函数原理
B、自写API函数
C、SYSENTER指令
D、硬编码_emit
E、模拟FindWindow函数
(Analysis of A, API function principle
B, write API function
C, SYSENTER instruction
D, hard coded _emit
E, simulating FindWindow function
)
- 2014-01-03 06:25:48下载
- 积分:1
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FingerPrint
说明: 这是用于指纹识别的matlab的程序,完整的哦,共享,也许有用哈(finger)
- 2010-04-29 18:05:59下载
- 积分:1
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dbscan
数据挖掘,聚类分析,DBSCAN C++的实现,(Data mining, clustering analysis, DBSCAN C++ Realization)
- 2007-12-26 14:53:12下载
- 积分:1
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113172219hog
description phog en matlab
- 2009-09-24 23:21:58下载
- 积分:1
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SADFSA
这是21寸定位压合源代码(it s very inportent)
- 2013-11-15 19:37:11下载
- 积分:1
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qichelilun
本程序为汽车理论第五版课后习题程序,采用matlab编程,经测试均为正确结果(The procedures for the car the theoretical fifth edition of the after-school exercise program, using matlab programming, has been tested and are the correct results)
- 2013-05-07 13:35:00下载
- 积分:1
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2DMaxima
在二维空间里有两个点A=(X1,Y1)和B=(X2,Y2),如果X1>X2并且Y1>Y2 ,我们认为A优于B,A是这个集合的最大极值点,在给定的二维空间里的N个点的集合S中,找出最大极值点。(In two-dimensional space, there are two points = A = (X1, Y1) and B (X2, Y2), if the X1 and Y1 > X2 > Y2, we think that A is superior to B, A is the biggest extreme value point of the set, in A given set of N points in the two-dimensional space S, find out the most extreme value point.)
- 2013-12-24 21:02:56下载
- 积分:1