matlab-function-Daquan

本文为MATLAB一篇详细的教程，看完之后入门应该会容易的多(This article gives a detailed tutorial MATLAB, after reading the entry should be much easier)

直接序列扩频仿真实例，产生m序列，然后进行扩频通信，对初学者很有用啊(Direct Sequence Spread Spectrum simulation example, useful for beginners )

用matlab编写的图像特征提取程序，其中包括一个提取8维HSV颜色直方图特征的函数，一个可以批量处理图像的主程序。(Prepared using matlab image feature extraction procedures, including an 8-dimensional HSV color histogram extracted feature functions, one of the main program can batch process images.)

说明：  MATLAB实现遗传算法求函数最大值，可以改变变量数目，函数形式(Seeking maximum MATLAB Genetic algorithms function, you can change the number of variables, functional form)

MATLAB爬虫程序，获取指定时间段的所有上市公司公告文本。(A MATLAB spider can fetch the published texts by A-stock companies in certain period.)

matlab 代码 matlab在数学建模中的应用 机器学习 大数据处理 matalb 数学建模(a a a a a a a a a a a a aa a a)

用于在MATLAB中绘制多坐标轴，将多个变量绘制在一张图中(MATLAB is used to draw multiple axes, multiple variables are plotted in a graph)

Considered a 16QAM communication system. The information rate is 2 Mb/s and the carrier frequency is 12 GHz. Assumed perfect synchronization. a) Simulated the system if the channel is AWGN and draw bit error rate of the system versus Eb/No. Compare the results with what you obtain in theory. b) Considered (15,11) Hamming code. Apply this code into the above system. Compare the results with what you obtain in theory. c) Simulated uncoded system if we have a Doppler Spread due to mobile movement in the channel. Simulate and draw the bit error rate of the system for maximum mobile speed 42.3 Km/Hour. No equalizer is used in the system. d) Applied coding of part (b) into the system of part (c). Simulate the system and discuss the results. e) Designed an interleaver for the system of part (d) to improve the coded performance results. Simulated the system.

this program is designed for solving the one-dimensional photonic structure for 1D multilayer structure using data in book, it get correct results.

clc close all clear all I=imread( desert.jpg ) [r c]=size(I) bs=16 Block Size (8x8) nob=(r/bs)*(c/bs) Total number of 8x8 Blocks Dividing the image into 8x8 Blocks kk=0 for i=1:(r/bs) for j=1:(c/bs) Block(:,:,kk+j)=I((bs*(i-1)+1:bs*(i-1)+bs),(bs*(j-1)+1:bs*(j-1)+bs)) end kk=kk+(r/bs) end Accessing individual Blocks figure imshow(Block(:,9,1)) This shows u the fist 8x8 Block in a figure window figure imshow(Block(:,:,2))