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Kalman-leraning-and-application
详细介绍了Kalman滤波的理论知识,应用原理和应用环境(Kalman filter described in detail the theory of knowledge, theory and application environment application)
- 2011-05-01 15:48:34下载
- 积分:1
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polynomial_synthesis
Code to obtain the filtering function polynomials F(s), E(s) and P(s), and the constants eps and eps_r from transmission zeros, with Cameron s method.
- 2013-07-15 18:45:31下载
- 积分:1
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FIR
FIR低通滤波器的编程实现,针对的是一维信号处理(The FIR low pass filter for programming is one dimensional signal processing)
- 2014-12-23 09:21:08下载
- 积分:1
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household-givens
运用matlab编程语言,实现利用Householder变换和Givens变换求解矩阵的QR分解(Use matlab programming language, the realization and the Givens transformations using the Householder transformation matrix QR decomposition to solve)
- 2013-10-06 20:54:14下载
- 积分:1
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35_2
实现语音的处理,如语音分离、语音去噪、变频、回旋、回声等功能(Voice processing, such as speech separation, de-noising voice, frequency, swing, echo, and other functions)
- 2021-04-09 18:48:59下载
- 积分:1
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Gaborfiltering
一种改进型Gabor滤波方法。此程序可以Gaobr的滤波效果。并且是分4个不同的方向滤波。(An improved Gabor filtering method.)
- 2013-11-20 10:28:23下载
- 积分:1
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Simulink-fuzzy-control-
这个是我找了很久,很有用的一篇文章,虽然说不是什么好学校,大牛们写的,但是对于初学模糊控制器加入simlink中还是很有用的。(fuzzy control、 nine-zero、simulink)
- 2011-12-14 10:16:21下载
- 积分:1
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MATLAB-MISTAKES
matlab编程时常见错误,如果越到问题,可以很好地帮助你解决出现的问题。(This book tell you how to deal with mistakes about the matlab programming)
- 2012-01-21 18:50:08下载
- 积分:1
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abouthomework
用周期图法求出的功率谱曲线和burg算法求出的AR功率谱曲线(p=50)(Periodogram calculated using the power spectrum curves and burg algorithm to derive the AR power spectral curve (p = 50))
- 2007-12-19 11:11:08下载
- 积分:1
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LTE_System_Level_1.4_r570
To solve this instance of the decision problem we must determine whether there is a truth value (TRUE or FALSE) we can assign to each of the variables (x1 through x4) such that the entire expression is TRUE. In this instance, there is such an assignment (x1 = TRUE,x2 = TRUE, x3=TRUE, x4=TRUE), so the answer to this instance is YES. This is one of many possible assignments, with for instance, any set of assignments including x1 = TRUE being sufficient. If there were no such assignment(s), the answer would be NO.
- 2012-04-23 22:00:12下载
- 积分:1