fast_distance_map_caculate

提出了一种大容量的可逆信息隐藏算法的详细实现方案。利用图像直方图中的多个零点或者最小点, 通 过修改图像像素的灰度值来隐藏信息, 并通过统计分析给出常用的信息隐藏的模型和算法。(Presents a large reversible capacity detailed information hiding algorithm implementations. Using the image histogram, or the minimum number of zero points, by modifying the image pixel gray value to hide the information, and is given by commonly used statistical analysis model and algorithm for information hiding.)

利用python和opencv拼接两张图片(Splicing two pictures using Python and opencv)

经过改进的快速的双边滤波器算法，主要是先下采样，然后进行滤波，最后再进行上采样(Improved bilateral rapid filter algorithm is the first major down-sampling, and then filtered, and finally to the sampling)

用C语言实现位图格式的图像读取功能，可直接使用。(read BMP by C ,can be used directly.)

一种鱼眼镜头校正算法的MATLAB实现，附论文及源代码(A MATLAB implementation of fisheye lens correction algorithm)

图像分类程序，此图像分类采用 SIFT + Kmeans 聚类的方法，然后调用 MLP 对其特征进行分类处理，速度实现比较快，正确率高(Image classification procedures, the use of this image classification method SIFT+ Kmeans clustering, and then call the MLP classification of its features, faster speed to achieve the correct rate)

检测图片中的角点，将图片读入后转换为灰度图以便处理。 2.通过用Dx=[-1,0,1;-2,0,2;-1,0,1]和灰度图片的矩阵卷积得到灰度图片在x方向上的导数矩阵Ix，矩阵中（i，j）处的元素代表灰度图片矩阵（i，j）处在x方向的导数Ix(Detection of corners in a picture)

基于RANSAC算法的图像匹配过程，包括提出该算法的文章以及文章中所提到的所有程序代码，可以实现具有高度异常点的图像匹配过程。(RANSAC algorithm based on image matching process, including all the program code of the algorithm proposed article and the article mentioned, the image matching process can be achieved with a high degree of abnormal points.)

用平均背景法去除背景，算法思想比混合高斯模型和codebook模型简单，适合提取背景变化较小的场景。用中值滤波去除掉产生的椒盐噪声(Average method to remove the background with the background, the algorithm thought codebook than the Gaussian mixture model and a simple model for extraction of small changes in background scene. With a median filter to remove salt and pepper noise generated)

用c语言编写的数字图像处理程序，图像读取，图像增强，图像复原，傅里叶变换，离散余弦变换都有(With the c language digital image processing, image scanning, image enhancement, image restoration, Fourier transform, discrete cosine transform has)