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shortest
说明: 科研项目里 最短路径的代码~~~~~,供大家使用希望有用~~(Research projects in the shortest path for the code we use hope ~~~~~, useful ~ ~)
- 2009-08-14 19:05:13下载
- 积分:1
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tuxiangfenge
基于遗传算法的双阈值图像分割,是用KSW方法。(Genetic Algorithm Based on dual-threshold image segmentation, is a method of KSW.)
- 2009-05-20 16:30:53下载
- 积分:1
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voice-last
System will automatically delete the directory of debug and release
- 2012-05-16 18:49:30下载
- 积分:1
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patternRecognition
this folder contain implemetation of three classifier in matlab
- 2009-10-19 00:45:01下载
- 积分:1
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jtyj
说明: 电力系统潮流的计算机辅助分析
本课题要求对一14节点的电力系统分别使用MATLAB和PSASP软件进行潮流计算及分析,其具体要求如下:
1)用MATLAB实现对该系统的潮流计算。需要MATLAB语言编制程序形成节点导纳矩阵、形成雅克比矩阵、用高斯消去法解修正方程式,并编写输出程序用以输出节点导纳矩阵、节点电压(包括电压的相角和幅值)、以及各支路的首端功率、末端功率和功率损耗,然后调式并在MATLAB运行环境下运行程序输出结果,再将结果制成表格。(Computer Aided Analysis of Power Flow)
- 2010-03-28 00:19:24下载
- 积分:1
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Channel-Estimation
信道估计,we will assume that the receiver knows your name, i.e., it knows s (and of course
x). Based on this knowledge, the receiver will estimate h using the MVU and MMSE method
(for the latter it is also assumed that the variance of the noise σ2 is known at the receiver).(Channel Estimation:we will assume that the receiver knows your name, i.e., it knows s (and of course
x). Based on this knowledge, the receiver will estimate h using the MVU and MMSE method
(for the latter it is also assumed that the variance of the noise σ2 is known at the receiver).)
- 2014-09-07 16:43:35下载
- 积分:1
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matlab-a-VC
Vc+_+调用matlab的一个实例,包括matlab源文件,VC源文件,以及word和pdf文件说明(Vc+_+ call matlab one instance, including the matlab source file, VC source files, as well as word and pdf file description)
- 2013-07-13 16:10:42下载
- 积分:1
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Chapter-6--Cellular-and-architecture
Matlab 软件基础学习资料,改章为第六章“元胞与构架”(Matlab software based learning materials, change chapter is Chapter 6, " Cellular and architecture." )
- 2013-07-23 20:24:53下载
- 积分:1
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indirect_fuzzy_5
implementation of fuzzy logic of vector control
- 2013-09-12 16:55:49下载
- 积分:1
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cmac
camac神经网络逼近函数,函数主要为z=(X^2+Y^2)*SIN(2*PI*X)(camac neural network approach, function primarily as z = (X ^ 2+Y ^ 2)* SIN (2* PI* X))
- 2014-12-10 21:41:25下载
- 积分:1