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Josephson
数值模拟了一类重要的超导器件Josephson结满足的方程。整个程序用matlab编成。(numerical simulation of an important class of superconducting Josephson junction device to satisfy the equation. The whole process into using Matlab.)
- 2007-04-24 22:42:51下载
- 积分:1
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leach
无线传感器网络分簇路由算法,很经典的,适合初学者练习使用(Clustering routing algorithms in wireless sensor networks, very classic, suitable for beginners to use
)
- 2014-11-07 13:44:56下载
- 积分:1
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liili
关于MATLAB的一些应用实例,我同学编的,大家可以看一下-(About some application examples of MATLAB, my classmates series, we can look at-)
- 2014-01-06 20:22:51下载
- 积分:1
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Behavior-Recognition-
基于时空兴趣点的行为识别期刊论文。本为以时空特征点出发的三维兴趣点检测。(Based on time and space of interest points behavior identification journal articles.This is to start at space-time characteristics of three dimensional interest point detection.)
- 2012-03-21 21:11:10下载
- 积分:1
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2DPOCHA
日本教授Ozaki所编写的二维相关光谱的计算可执行程序,国际上比较流行适用。(2dcos software to implement the nir spectroscopy analysis.)
- 2013-12-15 20:08:58下载
- 积分:1
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tiquwanggexiangsudian
说明: 在matlab开发环境中,提取图像的像素点,并保存(Development environment in matlab to extract the image pixels, and save)
- 2011-02-21 16:38:36下载
- 积分:1
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uneven
说明: 图像处理中将极坐标转换为笛卡尔左边的几个调用函数,包含bin,density 和ffgrid(in the image process,please convert the polar coordinate into castinate coordinate, there are some diaoyong functions ,include bin,density and ffgrid)
- 2011-03-24 10:51:33下载
- 积分:1
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PTS_OFDM
OFDM系统中用PTS算法降低系统的峰值平均功率比(OFDM system PTS algorithm used to reduce the peak-to-average power ratio)
- 2007-06-03 15:55:12下载
- 积分:1
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Helmholtz
Helmholtz方程的有限元解法,可以任意加密网格剖分,求解结果用图像显示.(Helmholtz equation finite element method, you can encrypt arbitrary mesh, the image display solution results.)
- 2013-11-08 18:48:40下载
- 积分:1
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hypot
抛物线法求解
方程的构造方法:给出[0,1]区间上的随机数(服从均匀分布)作为方程的根p*.
设你的班级数为a3,学号的后两位数分别为a2与a1,从而得到你的三次方程
例如:你的31班的12号,则你的方程是21x3+60x2+2x+a0=0的形式.
方程中的系数a0由你得到的根p*来确定.(parabolic equation method Construction Methods : given interval [0,1] on the random number (subject to uniform distribution) as the root equation p*. set up your classes at a3, after learning of the double-digit for a1 and a2, so you get the three equations for example : your 31 classes on the 12th, then your equation is 21x3 60x2 2x a0 = 0 forms. the equation coefficients a0 you get from the root of p* to determine.)
- 2014-04-25 08:18:59下载
- 积分:1