DisplayBTree

简单的一个链栈.即用链表实现的一个栈。可以做简单的插入、删除、查找等操作(this is a simple C++ program )

数据结构学习中提供的不错的源码，一个哈夫曼树类，利用了链队列存储结构。压缩包中有七个文件。(Data structure provided a good learning source, a Huffman tree class, the use of the chain queue storage structure. There are seven compressed file.)

用分治算法（O(nlogn)复杂度）实现寻找n个点中最邻近点对,输出为最邻近距离的平方(Looking for n points nearest point, the output of the nearest neighbor distance squared using the divide-and-conquer algorithm (O (nlogn) complexity))

some problems about c++.(car.cpp)

poj 实现堆结构的源代码。。。话说其实没什么实际功能好么(poj achieve heap structure of the source code. . . In fact, the actual function of saying okay nothing)

插入排序与合并排序的算法比较，比较两种算法的优劣(Comparison of insertion sort and merge)

流水线车间的零件加工排序问题，以达到最优的加工顺序，使加工时间最短或零件后期维护费用最少(Plant parts processing pipeline scheduling problem, in order to achieve optimal machining sequence, so that the processing time of the shortest or least parts later maintenance costs)

校园导航问题，设计你的学校的平面图，至少包括10个以上的景点（场所），每两个景点间可以有不同的路，且路长也可能不同，找出从任意景点到达另一景点的最佳路径（最短路径）。 要求： （1）以图中顶点表示校园内各景点，存放景点名称、代号、简介等信息；以边表示路径，存放路径长度等有关信息。 （2）为来访客人提供图中任意景点相关信息的查询。 （3）为来访客人提供任意景点的问路查询，即查询任意两个景点之间的一条最短路径。 （4）修改景点信息。 (Campus navigation problem, the design of your school s plan, at least more than 10 attractions (places), between every two spots can have a different way, and the long road may be different, to find spots to reach from any other attractions best path (shortest path). Requirements: (1) graph vertices represent various campus sites, storage sites name, code, profile and other information the side that path, the path length of storage of information. (2) the figure for visiting any sites offering information about the query. (3) any attractions for visiting guests ask queries of that query any two of the shortest path between sites. (4) modify the attractions information.)

说明：  简单的数据结构算法 在POJ上的题目 利用C++实现(Simple data structure algorithm in POJ on the subject using C++ Implementation)

马踏棋盘的贪心算法，8*8棋盘，基本上不用回溯。(horse riding chessboard of the greedy algorithm, 8* 8 chessboard, basically not retroactive.)