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MY_free
求解线性矩阵不等式的程序,简单明了,有注释,对于学习LMI有很好的帮助(Procedures for solving linear matrix inequalities, simple and clear, with annotations, very good for learning with the help of LMI)
- 2010-11-06 16:37:53下载
- 积分:1
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pdf
一些关于人脸检测的PDF,超有用的!!希望支持(Human Face Detection on the PDF, super useful! ! Wished to support the)
- 2009-03-12 19:47:50下载
- 积分:1
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dist2.m
A function that calculates radial distance between two given vectors
- 2010-12-02 12:54:33下载
- 积分:1
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EMD
说明: 经验模型分解程序,用于时间序列分析. (For EMD )
- 2010-04-22 16:48:37下载
- 积分:1
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Question1
说明: C++源代码,递归实现。原问题描述:鼓上蚤时迁到一个山洞里去盗宝,里面有n件宝贝,价值分别是a1,a2......an,并且满足ai大于a1+a2+....+a(i-1)的和。他身上有一个背包,能装的东西最大价值是K,他只能进洞一次,请问他最多能带出多少?
要求:输入K,n,a1,a2......an
输出:他能最多带出的宝物价值
(C++ Source code Recursive achieve. The original problem description: drum when flea盗宝going to move in a cave, there are n pieces of treasure, valued are a1, a2 ...... an, and to meet ai than a1+ A22B !....+ a (i-1) and. Him to have a backpack, things can hold the greatest value is K, he could only hole once, to ask him to bring out the maximum number of? Requirements: Enter K, n, a1, a2 ...... an output: he can bring out the maximum value of the treasures)
- 2008-12-02 21:07:25下载
- 积分:1
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Lab2_Solution
Code to make edge detection
extract this file and then read readme.txt file
- 2014-11-07 22:33:10下载
- 积分:1
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Face-Recognition-System-beldi
FACE DETECTE AND RECOGNITON AND FISHERFACE AND IGENFACE
- 2014-02-11 04:58:45下载
- 积分:1
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3次B样条曲线拟合
离散点曲线 进行3次B样条曲线拟合 包括节点参数化过程 基函数计算过程 控制点反求过程 到最后拟合曲线的显示(The discrete point curve is fitted with 3 B spline curves, including the node parameterization process, the basis function calculation process, the control point inversion process, and the final fitting curve display)
- 2017-08-21 17:28:15下载
- 积分:1
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image_Gabor_filter
关于Gabor图像滤波的matlab算法,经测可用(About Gabor matlab image filtering algorithms, measured by available)
- 2016-04-08 09:50:15下载
- 积分:1
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NMF
非负矩阵分解的人脸识别NMF 可正常运行 算法源码(Non-negative matrix factorization NMF for face recognition algorithms can be the normal operation of source)
- 2009-05-29 15:39:36下载
- 积分:1