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bpsk123

于 2006-05-17 发布 文件大小:11KB
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  matlab 学习资料psk123.rar 的matlab 学习资料psk123.rar(Matlab learning materials bpsk123.rar the Matlab learning materials bp sk123.rar)

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    五对角线性方程组求解程序. 速度奇快.一千阶,0.019秒 一万阶:0.56秒 10万阶:61秒. 数据输入结构见程序内英文说明.(Five linear equations solver. The speed of a swift pace. A thousand bands, ten thousand bands 0.019 seconds: 0.56 seconds 100,000 bands: 61 seconds. Data input structure see process description in English.)
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    说明:  stewart平台,六自由度并联摇摆台的反解控制算法,配有GUI界面,可以自定义角度,杆长等参数,设定动平台位姿即能得到电机参数(Stewart platform, inverse solution control algorithm of 6-DOF parallel swing table, with GUI interface, you can customize parameters such as angle, rod length, and set the position and attitude of the moving platform to get the motor parameters)
    2020-10-16 15:48:41下载
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    微粒子算法matlab代码:很南找到一个资料,和大家分享(Microparticle algorithm matlab code: I am the South to find a data, and share)
    2010-06-23 08:14:25下载
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    ipmsm speed control using a controller with trial purpose
    2009-11-17 08:37:52下载
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    2009-12-29 18:09:08下载
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  • shuxuejianmo_1
    说明:  某厂生产甲乙两种口味的饮料,每百箱甲饮料需用原料6千克,工人10名,可获利10万元 每百箱乙饮料需用原料5千克,工人20名,可获利9万元.今工厂共有原料60千克,工人150名,又由于其他条件所限甲饮料产量不超过8百箱.问如何安排生产计划,即两种饮料各生产多少使获利最大.进一步讨论: 1)若投资0.8万元可增加原料1千克,问应否作这项投资. 2)若每百箱甲饮料获利可增加1万元,问应否改变生产计划. (Factory production of beverages and B in two flavors, each box 100 need a drink six kilograms of raw materials, workers 10 to 100,000 yuan profit B beverage cartons per cent five kilograms of raw materials needed, workers 20, the profitability of 90,000 yuan. this plant a total of 60 kilograms of raw materials, 150 workers, and because other conditions do not yield a beverage cartons more than 8 per cent. ask what arrangements the production of projects, namely the production of two the number of drinks to make the biggest profit. further discussion : 1) if the investment 08,000 yuan to increase one kilograms of raw materials and asked whether we should make this investment. 2) If a beverage cartons per cent profit increase 10,000 yuan and asked whether or not to change the production plan.)
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