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ninelevelhbridge
matlab simulink model for a nine level h bridge inverter
- 2015-02-15 18:42:15下载
- 积分:1
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GMSK-Modem
GMSK信号调制和解调的仿真代码,包含一比特差分、2比特差分、鉴频等常用GMSK解调方案。(Modem matlab file for GMSK modulation and demodulation. The demodulation methods including one-bit differential and two-bit differentian decoding and frequency discrimination.)
- 2015-03-04 16:24:18下载
- 积分:1
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fingrt
finger print recognition algo in matlab
- 2015-02-09 18:42:14下载
- 积分:1
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LDA
线性判别分析法源代码,LDA算法,输出分类结果(Linear discriminant analysis method source code, to output the classification results)
- 2012-05-13 09:03:22下载
- 积分:1
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mygui
基于快速傅里叶变换的GUI设计,能对多个输入序列进行FFT分析,并在画面上显示出输入信号,经过FFT处理,经过IFFT处理的信号波形(GUI design based on the fast Fourier transform, FFT analysis of a plurality of input sequences, and displayed on the screen of the input signal after FFT processing, the signal waveform after the IFFT processing)
- 2012-11-05 22:49:58下载
- 积分:1
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yichuansuanfa4
通过遗传算法计算下列函数的全局最优值 y(t)=sum(x(t,:).*x(t,:))(Global calculate the following functions by genetic algorithms optimal value
y(t)=sum(x(t,:).*x(t,:))
)
- 2015-03-16 16:02:57下载
- 积分:1
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ga
说明: 使用“旋轮法正比选择”、“单切点交叉”和单点突变的遗传算法(Use " proportional to select the roller method," " single-cut point crossover" and the single point mutation in the genetic algorithm)
- 2010-06-29 11:59:05下载
- 积分:1
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MultiPGM0001
AT88 PROGRAMMER DIAGRAM
- 2010-08-21 21:43:31下载
- 积分:1
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10568436_400440276779902_115819654_n
this brogram to sum to number and show the result to the user
- 2015-01-03 10:46:50下载
- 积分:1
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szfxsy1
实验一:三次样条插值(P56,例6)
一、实验目的:
1) 掌握三次样条插值的运用
2) 了解拉格朗日插值在高次上的误差
二、实验环境:Matlab6.5
三、实验内容:
1) 给定函数f(x)=1/(1+x2),-5<=x<=5,节点xk=-5+k,(k=0,1,2…10),用三次样条插值求S10(x),S10’(-5)=f’(-5),S10’(5)=f’(5)。
2)作原函数f(x),拉格朗日插值函数Ln(x),三次样条差值函数Sn(x)。画出三个函数的图像,比较它们的区别。
(Experiment I: cubic spline interpolation (P56, cases of 6) First, the experiment was: 1) cubic spline interpolation to master the use of 2) understanding of Lagrange interpolation in high-error second, experimental environment: Matlab6 .5 c, experimental elements: 1) a given function f (x) = 1/(1+ x2),-5 <= x <= 5, node xk =- 5+ k, (k = 0,1,2 ... 10), using cubic spline interpolation for S10 (x), S10 (-5) = f (-5), S10 (5) = f (5). 2) for the original function f (x), the Lagrange interpolation function Ln (x), cubic spline difference function Sn (x). Draw the three functions of images, compare the difference between them.)
- 2009-01-18 23:06:15下载
- 积分:1