wsn_matlab_leach

在偏微分方程的数值求解中，有一类很重要的问题就是求解有奇异点的泊松方程，此程序是用C写的并行程序，能极大的提高泊松方程的求解(In the numerical solution of partial differential equations, there is a class of very important issues that have a singular point of solving the Poisson equation, this program is written in C parallel programs, can greatly improve the solution of the Poisson equation)

Well, this is a Visual Studio program which monitors temperatures Arduinoin background!

分簇协议的改进协议DEEC的matlab代码，绝对正确，大家可以下载试试，对学习WSN路由协议很有帮助。(Improved clustering protocol agreement DEEC matlab code, absolutely correct, you can download to try, to learn helpful WSN routing protocol.)

这是关于MATLAB和CShaarp混合编程的资料，讲解的很清楚 (About the MATLAB and CShaarp hybrid programming information, explain very clearly)

程序dijkstra,C++语言的，可以运行，做数学建模竞赛会用到的(dijkstra,C++，for math modelling)

真的是一个好程序，LDPC码的完整的编译码，matlab编写的元胞自动机。( Really is a good program, Complete codec LDPC code, matlab prepared cellular automata.)

这是一本很经典的教程！不知道有人传过没有。先传上来，希望有用(This is a very classic tutorial! Some people do not know they could not mass. Chuan-first onto the hope that useful)

PFC 的原理与分析设计 我们作比赛的资料(Principle and Analysis of PFC design we make the game data)

某市有一码头，每次仅容一辆船停泊装卸货，由于经常有船等候进港，部分人提出要扩建码头。经过调查历史资料发现，码头平均每月停船24艘，每艘船的停泊时间为24±20小时，相邻两艘船的到达时间间隔为30±15小时，如果一艘船因有船在港而等候1小时，其消耗成本为1000元。经预算，扩建码头大约需要1350万元，故市长决策如下：如果未来五年内停泊船只因等候的成本消耗总和超过扩建码头花费则扩建码头，否则，不予扩建。因此，希望你能够帮助市长做出决策。此问题已知到达的大概时间和大概停泊时间，对于此问题用概率统计的方法来做比较复杂，可用程序随机产生到达时间和停泊时间来模拟未来五年内船的停泊，多次模拟预测停泊情况，以做出决策(。-Problem in a city with a terminal expansion dock, each only allow a boat moored loading and unloading, as often there are waiting boat into port, some people proposed to expand pier. Terminal stopping 24 per month, per vessel berthing time of 24 ± 20 hours, the arrival of two adjacent vessels interval 30 ± 15 hours, if a ship due to boat in the harbor while waiting for one hour, and its consumption cost of 1,000 yuan. The budget of about 13.5 million yuan expansion dock, so the mayor decision as follows: If a ship is moored next five years, the cost of waiting more than the sum of consumption spending is expanding marina pier extension, otherwise, not expanded.)

一维的有限差分源代码，，matlab，简单易学，方面使用，有限差分的优点就是计算简便高效(One-dimensional finite difference code)