proportionalFairScheduler

this code is tell about segmentation of an image

matlab的pso工具箱 很好用 直接不用编程序了 只需要修改一下函数就可以(The good toolbox matlab pso not directly programmed with the only change it can function)

说明：  VC++中使用MATLAB的C++数学库和MCC生成的程序.txt(VC++ Use MATLAB)

实现道路检测，能从图像中自动检测并分割出道路，用于交通检测(Achieve road detection, the image automatically detect and segment the road for traffic detection)

主要介绍 matlab微分方程解法 里面的例子较多(mathematical modelling in matlab)

Parzen窗法，由样本求概密估计，例为一维正态分布和双峰均匀分布，内附随机数生成的原理说明。(Parzen window method, by the sample density estimate for estimated Example for one-dimensional normal distribution and bimodal uniform distribution, random number generator containing a description of the principle.)

1、观察采样引起的混叠。 2、判别离散时间系统的时不变性。 3、利用卷积计算信号通过FIR滤波器的输出，并观察输出信号的input-on暂态、input-off暂态和稳态阶段。 (One to observe the sampling due to aliasing. 2, determine the time invariant discrete-time systems. 3, the use of convolution calculation of the signal through the FIR filter output, and observe the output signal of the input-on transient, input-off transient and steady-state phase.)

描绘PSO算法并且获得动态图像动画 discribe a PSO and get an animation(discribe a PSO and get an animationdiscribe a PSO and get an animation)

Conduct a digital system ( electronic lock ) using hierarchic methodology . An electronic lock is a device that allows access or opening of a system , as long as the key or combination to enter match with which it is predefined in said lock .

数值方法计算传热问题实例 边长为200×200mm的二维矩形材料内的稳态温度分布。上侧和左侧维持恒壁温；下侧为绝热；右侧为对流换热条件。具体参数为： 材料的导热系数=20w/m• k； 上侧温度t1=100℃ 右侧流体温度tf=20℃ 表面传热系数 h分别为1w/m2• k和100 w/m2• k 左侧温度t2=20℃ 下侧绝热(Numerical method to calculate the heat transfer problem instance side of 200 × 200mm rectangular two-dimensional steady-state temperature distribution within the material. On the left side and to maintain constant wall temperature lower side of insulation the right side of the convective heat transfer conditions. Specific parameters are: thermal conductivity of the material = 20w/m • k on the side of the temperature t1 = 100 ℃ right side of the fluid temperature tf = 20 ℃ surface heat transfer coefficient h were 1w/m2 • k and 100 w/m2 • k temperature t2 = 20 ℃ left side of the insulation under)