ActiveX-dll

rockplayer播放器，应用程序编程源码，很好的参考资料。(Rockplayer player, application programming source code, a good reference.)

给出了几种用java语言编写的登陆界面的例子，希望对初学者有帮助(Given several landing using java language interface examples, I hope to help beginners)

将基础知识，高级运用，框架知识综合到一起，源码demo(Fundamentals and advanced the framework of the use of knowledge are integrated together, source demo)

j2ee struts + hibernate project

java编程：自己编写的地名相似度匹配算法包括地名相似度、地理位置相似度(java programming: write their own names, including names similarity similarity matching algorithm, the geographical similarity)

说明：  用于转换SQL server数据自定义字段为数据库定义字段;(transform for SQL server databases selfdefined field;)

分布式温控系统基本要求 1. 中央空调是冷暖两用，但一次只能使用一种温控装置。当设置为供暖时，供暖温度控制在25°C～30°C之间，当设置为制冷时，制冷温度控制在18°C～25°C之间。 2. 中央空调具备开关按钮，只可人工开启和关闭，中央空调开启后处于待机状态。当关闭后，不响应来自房间的任何温控请求。当有来自从控机的温控要求时，中央空调开始工作。当所有房间都没有温控要求时，中央空调的状态回到待机状态。 3. 房间内有独立的从控空调机，但没有冷暖控制设备。从控机具有一个传感器，实时监测房间的温度，并与从控机的目标设置温度进行对比，决定是否需要制冷或制热，并向中央空调机发出请求。如果从控机发出的请求和中央空调设置的冷暖控制状态发生矛盾时，以中央空调机的状态优先，即中央空调机不予响应。 4. 从控机只能人工方式开闭，并通过控制面板设置目标温度，目标温度有上下限制。所有房间的初始目标温度由中央空调机设置，每个房间的空调机开启时要读取中央空调机预置的房间温度。温度升降范围应该在目标温度的上下1 °C。房间不考虑大小和管道的分布及大小问题，在达到目标温度后，房间的温度每分钟上下变化0.1°C。 (Basic requirements of a distributed temperature control system 1. Central air conditioning is the well-being of dual-use, but can only use a thermostat device. When set to heating, the heating temperature at 25 ° C ~ 30 ° C, and when set to cooling, the cooling temperature at 18 ° C ~ 25 ° C between. 2. Central air conditioning with switch buttons can only be manually opened and closed, central air-conditioning turned on in standby mode. When closed, do not respond to a request from the room of any thermostat. When the machine from temperature control from the control requirements, central air-conditioning work. When all rooms are no thermostat demand, central air condition back to standby. 3. Room independent from the control air conditioning, but no climate-control equipment. From the control machine with a sensor, real-time monitoring the temperature of the room, and with the goal set from the control unit compares the temperature to determine the need for cooling or he)

Java五子棋编程 (Gobang Java Programming)

XFire+WebService+Spring简单Demo(XFire+WebService+Spring Demo)

1. 分别使用Vector、Hashtable、Stack，ArrayList、LinkedList和HashSet作为容器类，实现以下要求： (1) 向容器中添加1,000,000个随机整数。 (2) 遍历容器中的所有元素。 (3) 随机产生100,000个整数，在容器中查找这些整数。 (4) 随机产生100个整数，从容器中删除这些整数。 (5) 统计完成以上各个操作需要的时间。 比较一下不同操作在不同数据结构下的性能差异。程序文件命名为Exe5_1.java。 (51 respectively using Vector, Hashtable, Stack, ArrayList, LinkedList and HashSet as the container class, to achieve the following requirements: ( 1) are added to the container 1000000 random integers. ( 2) to traverse all the elements in the container. ( 3) 100000 randomly generated integer, in the container to find these integers. ( 4) random produces 100 integers, is removed from the container of these integers. ( 5) complete the statistics above each operation requires time. Compare the different operating at different data structure performance differences. Program file named Exe5_1.java )