jianluoshengtezheng

卷积码的matlab结构图，很实用，很简洁，欢迎大家下载(Convolution matlab code structure is very useful, very simple, welcome you to download)

说明：  Embedded Control Systems in C/C++: An Introduction for Software Developers Using MATLAB(Embedded Control Systems in C/C++: An Introduction for Software Developers Using MATLAB The author of this text illustrates how to implement control systems in your resource-limited embedded systems. Using C or C++, you will learn to design and test control systems to ensure a high level of performance and robustness)

ieee9节点配电网采用前推回带法计算电压，电流(Ieee9 node distribution network USES the former back zone method to calculate the voltage, electric current)

软硬阈值函数和自定义的基于非线性变换阈值函数曲线图(Hard and soft threshold function and custom thresholding function based on nonlinear transformation curve)

基于免疫机制的动态多目标优化免疫算法[PDF](Dynam icMultiobjectiveOptim ization Immune Algorith Based on ImmuneM echanisms )

music算法程序，基本MUSIC算法仿真程序，进行DOA估计(MUSIC algorithm)

说明：  极化SAR(POLSAR)

现代信号处理中谱估计在matlab中的使用，使用大量的有限元法求解偏微分方程，BP神经网络用于函数拟合与模式识别，阐述了负荷预测的应用研究,实现串口的数据采集，针对EMD方法的不足。

1.分别在两个图中画出δ(n)和δ(n-2)，其中-10≤n≤10，画出U（n）其中-10≤n≤10。 2.分别在两个图中画出x1(n)=cos(2π×20×0.01×n)，0≤n≤10和x2(n)=(0.8)n，1≤n≤6。 3.由上一题，计算y(n)=x1(n)+x2(n)，并画图。(1. Draw the figure at two δ (n) and δ (n-2), where-10 ≤ n ≤ 10, draw the U (n) where-10 ≤ n ≤ 10. 2. Respectively in the two Draw the figure x1 (n) = cos (2π × 20 × 0.01 × n), 0 ≤ n ≤ 10 and x2 (n) = (0.8) n, 1 ≤ n ≤ 6. 3. from the previous question, calculate y (n) = x1 (n)+ x2 (n), and drawing.)

说明：  切换系统中经典研究模型，对切换控制策略进行验证。(The classical research model of handoff system verifies the handoff control strategy.)