inversion

Improved Binary DAC Codec

战场最新源代码大家一起研究一下。看看还有什么不对的地方进行最新的描述(大家一起研究一下。看看还有什么不对的地方进行最新的描述)

说明：  蒙特卡罗马尔科夫链学习相关知识，了解马尔科夫和蒙特卡罗常用方法。(Markov chain Monte Carlo to learn relevant knowledge, understanding common Markov and Monte Carlo methods.)

说明：  从方程组中消去一些未知函数及其各阶导数，得到只含有一个未知函数的高阶常系数线性微分方程(Eliminated from the equations of some unknown function and its first derivative, the only unknown function contains a higher-order linear differential equations with constant coefficients)

小波变换进行图像压缩 采用matlab编程 (Wavelet transform for image compression Using matlab programming)

DFT数字信号采集滤波器实例演示程序，很实用的一个小程序。(DFT filter digital signal acquisition example demo program, it is a small utility program.)

给定n位整数任意去掉其中k<=n位，剩下的数字按原次序排列组成一个新的正整数，且这个正整数最小(Given an arbitrary n-bit integers to remove where k < = n bits, the remaining number of original order of the formation of a new positive integer, and that this is the smallest integer)

扩展卡尔曼滤波程序，C语言仿真。包括卡尔曼滤波简介及其算法实现代码。(EKF simulation)

潮流计算程序，初始值使用高斯赛德尔法迭代所得，具有很高的精度和求解效率。(Flow calculation procedures, the initial value of iteration proceeds using high Sisaideer method with high accuracy and solution efficiency.)

一道程序编译顺序的考题，涉及到函数调用的先后顺序及运算符号的优先级等问题。下面我展开给你讲。 C的程序编译总是从main函数开始的，这道题的重点在“fun（（int）fun（a+c,b）,a-c）） ”语句。 系统首先要确定最外层 fun()函数的实参，第一个参数的确定需要递归调用fun()函数（不妨称其为内层函数）。内层函数的两个参数分别为x=a+b=2+8=10、y=b=5,执行函数体x+y=10+5=15,于是得外层函数的参数x=15。其另一个参数y=a-c=2-b=-6,再次执行函数体,得最终返回值x+y=15+(-6)=9。 (Compiling together the sequence of test procedures, involving the sequence of function calls and operator symbols, such as the priority problem. Now I give you to start speaking. Procedures for C compiler always start from the main function and at这道题the focus of " fun ((int) fun (a+ c, b), ac)) " statement. System must first determine the most outer layer of fun () function of real parameters, the first parameters of recursive calls required fun () function (may be called the inner function). Inner function separately for the two parameters x = a+ b = 2+8 = 10, y = b = 5, to execute the function body x+ y = 10+5 = 15, then the outer function parameters were x = 15 . Its another parameter y = ac = 2-b =- 6, once again to execute the function body may eventually return the value of x+ y = 15+ (-6) = 9.)