amuse

利用matlab实现维特比编解码，采用的是汉明距离，[3 1](Using Viterbi decoding matlab implementation, using the Hamming distance, [31])

Short code to create shading around a mean. Input is a matrix with rows of observations

用遗传算法实现道路图像分割，运行良好，方法简单，欢迎下载(Road image segmentation using genetic algorithm, works well, simple methods are welcome to download)

Realtime sound acquisiton and processing using matlab

说明：  采用LMS算法的盲均衡仿真程序，挺简单的，大家可作为参考(using LMS blind equalization algorithm for the simulation program, quite simply, we can reference)

根据csdn版主VC和matlab混编的文章，写成的VC调用matlab生成的动态函数库显示图片。(vc function calls matlab s function )

读取两个文件夹中对应的图像，将两幅图像进行小波分解，修改小波系数将两幅图像的小波系数进行融合，融合后进行反变换，得到小波分解融合后的图像。(Read the two folders corresponding image, two images using wavelet decomposition, wavelet coefficients modified wavelet coefficients of the two images are fused fusion inverse transform, wavelet decomposition obtained after fusion.)

说明：  某厂生产甲乙两种口味的饮料,每百箱甲饮料需用原料6千克,工人10名,可获利10万元 每百箱乙饮料需用原料5千克,工人20名,可获利9万元.今工厂共有原料60千克,工人150名,又由于其他条件所限甲饮料产量不超过8百箱.问如何安排生产计划,即两种饮料各生产多少使获利最大.进一步讨论: 1)若投资0.8万元可增加原料1千克,问应否作这项投资. 2)若每百箱甲饮料获利可增加1万元,问应否改变生产计划. (Factory production of beverages and B in two flavors, each box 100 need a drink six kilograms of raw materials, workers 10 to 100,000 yuan profit B beverage cartons per cent five kilograms of raw materials needed, workers 20, the profitability of 90,000 yuan. this plant a total of 60 kilograms of raw materials, 150 workers, and because other conditions do not yield a beverage cartons more than 8 per cent. ask what arrangements the production of projects, namely the production of two the number of drinks to make the biggest profit. further discussion : 1) if the investment 08,000 yuan to increase one kilograms of raw materials and asked whether we should make this investment. 2) If a beverage cartons per cent profit increase 10,000 yuan and asked whether or not to change the production plan.)

说明：  《射频通信电路》陈邦媛著课后答案详细版 详细讲解了各种解答方案，对于学习射频通信电路有很好的帮助(&quot RF communication circuits,&quot Chen Bangyuan version with more elaborate after-school answer a variety of answers to the program, the RF communication circuit for learning with the help of good)

计算互信息，通过状态转移概率和分支度量进行前向递推(calculate the mutual information)