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Harris1
我在网上下载的,感觉不错,给大家推荐一下,希望能有所帮助(very good)
- 2010-05-07 16:17:39下载
- 积分:1
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ESPRIT_2D
这篇代码介绍了一种阵列信号处理的一种算法,具有很大的作用。(This code describes an algorithm for an array signal processing, has a big role.)
- 2021-04-23 09:38:48下载
- 积分:1
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OBMC
此代码通过OBMC(重叠块运动补偿)实现了视频插帧运算。利用已有的运动向量和前后两帧图像,通过OBMC算法,求出中间内插帧(This video frame interpolation operator code OBMC (overlapped block motion compensation). Using the existing motion vectors and two of front and rear image is obtained through the the OBMC algorithm, intermediate interpolated frame)
- 2020-10-12 23:47:31下载
- 积分:1
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12121FingerprintRecognition.rar
the same with what i have uploaded before.
- 2010-10-06 01:42:36下载
- 积分:1
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masvect
Simulation sous simulink, de la machine asynchrone triphasée avec commande vectorielle, et modele dq de la MAS
- 2010-12-10 00:48:42下载
- 积分:1
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matlab
陈仲生 《基于matlab7.0的统计信息处理》(陈仲生" matlab7.0 based on statistical information processing" )
- 2009-06-06 01:13:04下载
- 积分:1
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edge_xiangwei
利用改进的相位一致性原则实现图像的边缘检测,效果非常好,内含两幅实验图像与四个子代码。(simulating using the principle of Phase consistency to image edge detection, the effect is very good, including two experimental image and the four sub-code.)
- 2011-05-15 09:49:37下载
- 积分:1
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chap15
人脸识别中核心算法的MATLAB软件实现例程(The core algorithm of face recognition in MATLAB)
- 2013-11-30 10:43:17下载
- 积分:1
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音乐播放(音频波形)
播放音乐
- 2021-05-06下载
- 积分:1
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Chapter6
数值解法
例1 用改进的欧拉方法求一阶方程初值问题的
数值解
例2 数学摆的运动方程与近似方程数值解比较
例3 四阶龙格库塔公式求数值解
Matlab实现求数值解
例1 求初值问题y =x*sin(x)-y,y(0)=0的数值
解.先编辑一个定义方程的ODEF函数文件
ODEfun1.m.
例2 求方程组初值问题的数值解,按指定步长
0.05划分节点.
例3 按指定的精度求高阶方程初值问题的数值解.(Numerical Solution of the law a method of using the improved Euler' s equation of order to a first-order initial value problem of the numerical solution of cases of two mathematical pendulum equations of motion compared with the approximate numerical solutions of equations of three cases of fourth-order Runge-Kutta numerical solution of the formula Matlab order to achieve the numerical solution of demand cases seeking an initial value problem y ' = x* sin (x)-y, y (0) = 0 the numerical solution. first, the definition of an equation editor ODEF function file ODEfun1.m. cases of two demand equations initial value problem of numerical solution, according to the specified division of the node step 0.05. Example 3 according to the specified precision of seeking higher-order equation of the numerical solution of initial value problem.)
- 2010-02-05 23:14:41下载
- 积分:1