csminit

线性调频脉冲压缩雷达仿真程序.仿真程序模拟产生理想点目标的回波，并采用频域相关方法（以便利用FFT）实现脉冲压缩。(线性调频脉冲压缩雷达仿真程序)

关于三次样条插值在matlab中的实现，给出了源程序(Construction and Realization of Cubic Spline Interpolation Function )

this is classifier using Euclidean distance measure for palm print recognition

boost circuit for power electronics

电力系统17机动态稳定性测试数据，包含162条母线潮流数据和发电机的经典模型数据，潮流数据采用IEEE标准数据模型，适合基于matlab工具箱的电力系统动态仿真研究。(This 17 generator dynamic stability test case, which includes a 162 bus power flow data file)

摘　要 文章以空间监控系统为背景,深入研究了JPEG图像压缩标准的实现方法,并基于FPGA对其进行了实现和优化。文中给出了详细的实现方法和优化过程,测试表明达到了很好的效果。 简单介绍了有损静态图像压缩当前有两种比较流行的标准JPEG和JPEG2000。说明了用JPEG方法压缩的原因。 介绍JPEG基本原理：JPEG对灰度图像的压缩处理过程主要包括:图像分割,离散余弦变换(DCT),量化(Quantization),“Z”形排序(Zigzag Scan),差分脉冲编码调制(Differential Pulse Code Modulation,DPCM)对直流系数(DC),行程长度编码(Run-Length Encoding,RLE)对交流系数(AC),霍夫曼(Huffman)编码等。 JPEG标准的特点是离散余弦变换。 比较详细介绍压缩系统的构成和实现。实现提及步骤， JPEG压缩模块设计和编码模块实现细节。 (Abstract Article in the space monitoring system for the background, in-depth study of the JPEG image compression standard implementation methods and carried out based on FPGA implementation and optimization. In this paper, a detailed method of implementation and optimization of the process, testing showed that to achieve good results. Easy introduction of harmful static image compression has two kinds of comparisons that the current popular standard JPEG and JPEG2000. Illustrated by the reasons for JPEG compression method. JPEG introduce the basic principles: JPEG compression of gray-scale image processing include: image segmentation, discrete cosine transform (DCT), quantization (Quantization), "Z"-shaped sort (Zigzag Scan), differential pulse code modulation (Differential Pulse Code Modulation, DPCM) on the DC coefficient (DC), Run Length Encoding (Run-Length Encoding, RLE) of the exchange coefficient (AC), Hoffman (Huffman) coding. JPEG standard is characterized by discrete )

matlab的zernike矩算法，可计算R(matlab zernike)

满足分数布朗运动的资产价格的走势的模拟程序。(Value s Simulation)

hht_toolbox工具箱用 时频分析必备 大家共同学习(HHT toolbox for HHT time-frequency analysis )

PSO algorithm for solving basic question. It combine with c1 and c2, which their sum are between 0 to 4.