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ComputerMATLABUsingMatlab
Matlab book Engineering Matlab Programming Engineering Matlab Programming
- 2009-03-19 19:57:16下载
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base_kmeans_imgseg_medicalimg
lMATLAB, which stands for MATrix LABoratory, is a state-of-the-art mathematical software
package, which is used extensively in both academia and industry. It is an interactive program
for numerical computation and data visualization, which along with its programming capabilities
provides a very useful tool for almost all areas of science and engineering. Unlike other
mathematical packages, such as MAPLE or MATHEMATICA, MATLAB cannot perform
symbolic manipulations without the use of additional Toolboxes. It remains however, one of the
leading software packages for numerical computation
- 2010-12-31 18:42:41下载
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Fig.6
Stud. Appl. Math. 118, 153-197 (2007)关于solitons的一篇文章,figure6的编程,主要是运用牛顿迭代法进行数值模拟的。(Stud. Appl. Math. 118, 153-197 (2007) on the solitons in an article, figure6 programming, primarily using Newton' s iterative method of numerical simulation.)
- 2010-03-11 10:21:31下载
- 积分:1
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matpower3.0b3
说明: 电力系统最优潮流程序,可以应用于电力市场下的最优潮流计算。适合电力系统专业的同仁使用(optimal power flow procedure can be applied to the electricity market under the optimal power flow calculation. Power systems for the professional colleagues use)
- 2005-09-10 20:16:21下载
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PSO_function
这个程序是粒子群优化算法程序,用Matlab实现,非常简单。只有几十行代码。且已经过调试(This program is a particle swarm optimization procedures, using Matlab implementation is very simple. Only a few dozen lines of code. And has been commissioning)
- 2011-06-08 15:14:02下载
- 积分:1
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gray-matching
matlab 的灰度匹配算法例子,简单易懂,对初学的人比较适用(gray matching algorithm matlab example, easy to understand, more suitable for beginners who)
- 2014-02-24 23:01:33下载
- 积分:1
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被动调Q速率方程组仿真
基于Nd:YAG/Cr4:YAG的半导体激光器被动调Q ,速率方程组仿真(经典四阶龙格库塔法)。(the rate equation simulation of Nd:YAG/Cr4:YAG passively Q-switched solid laser.)
- 2021-03-30 09:39:10下载
- 积分:1
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antclustering
ant clustering and rgb
- 2010-07-01 16:55:16下载
- 积分:1
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To_plot_the_Blackman_window_for_filters
blackman window for filter matlab code with example
- 2011-01-14 15:12:40下载
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exercise
根据公式I(n-1)=(1-In)/n 令I11=0计算I1 到I10;
根据公式In=1-nI(n-1) 令I0=0.6321 计算I1到I7;
根据公式X2=a , 令a=2,计算X的值。(According to the formula
I(n-1)=(1-In)/n ,set I11 equals zero,and count I1 to I10.
According to the formula
In=1-nI(n-1),set I11 equals zero,and count I1 to I10.
According to the formula X square equals a ,set a equals two ,then calculate X
)
- 2010-05-09 21:54:01下载
- 积分:1