elm

说明：  精馏塔的PID控制，对于精馏塔来说效果比较好。(Distillation of the PID control, results were better for the distillation.)

Image processing source code @ GIST

matlab课程编程【谷速软件】4RRR平行平面机械臂 (matlab programming courses [software] 4RRR Valley speed parallel plane manipulator)

基于多智能体的一致性算法，包括连续，和离散的一致性算法。(Consistency algorithm based on multi-agent, including continuous, and the consistency of the discrete algorithm.)

用于多通道滤波器组实现最优化设计,主要应用于图象处理(Used to realize multi-channel filter banks to optimize the design, mainly used in image processing)

matlab code for simple listbox control

排队问题仿真模型的代码，顾客到达时间和服务时间服从均匀分布。(Simulation model of the queuing code, the customer arrival time and service time uniform distribution.)

基于混沌理论的时间序列的系统多步预测函数(Based on the theory of chaos time series prediction function of the system)

　多输入多输出正交分频多工模拟器。 　　 　　正交分频多工:OFDM模拟器(外层函数) 　　 　　 　　create_channel:产生一个瑞利衰落信道复用,解的天线配置、正交分频多工结构、power-delay档案。 　　 　　 　　svd_decompose_channel:既然全网络知识是假设,在并行传输奇异值模式。这个函数分解这些频道模式。 　　 　　 　　BitLoad:适用bit-loading算法来实现预期的钻头和能量 (MIMO OFDM Simulator: OFDM.m: OFDM Simulator (outer function) create_channel.m: Generates a Rayleigh fading frequency-selective channel, parametrized by the antenna configuration, the OFDM configuration, and the power-delay profile. svd_decompose_channel.m: Since full channel knowledge is assumed, transmission is across parallel singular value modes. This function decomposes the channel into these modes. BitLoad.m: Apply the bit-loading algorithm to achieve the desired bit and energy allocation for the current channel instance. ComputeSNR.m: Given the subcarrier gains, this simple function generates the SNR values of each channel (each singular value on each tone is a separate channel). chow_algo.m: Apply Chow s algorithm to generate a particular bit and energy allocation. EnergyTableInit.m: Given the SNR values, form a table of energy increments for each channel. campello_algo.m: Apply Campello s algorithm to converge to the optimal bit and energy allocatio)

拉格朗日算法已知三组温度与压力数据:(3,53.5) (4,55.3) (5,56.2)求4.15对应的值为55.492375，结果正确。如果将以上数组顺序颠倒，已知压力55.492375求对应的温度，结果为4.185739，可以看到上下两个结果误差较大，就是说不能象这样去颠倒顺序去求值的。但是实际上我们可能经常要求知道压力去求温度，那么遇到这样的情况，只能采用试算法：一种简单的方法就是二分法迭代，书上都有介绍就不多讲了。(Lagrange method已知三组温度与压力数据:(3,53.5) (4,55.3) (5,56.2)求4.15对应的值为55.492375，结果正确。如果将以上数组顺序颠倒，已知压力55.492375求对应的温度，结果为4.185739，可以看到上下两个结果误差较大，就是说不能象这样去颠倒顺序去求值的。但是实际上我们可能经常要求知道压力去求温度，那么遇到这样的情况，只能采用试算法：一种简单的方法就是二分法迭代，书上都有介绍就不多讲了。)