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matlab-uploads
Matlab course project files
- 2014-12-31 18:34:57下载
- 积分:1
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G
GM工具积分属性修改-by_精湛架设-奇迹私服一条龙-奇迹SF版本(GM Tools integral attribute modification-by_ superb erection- PW train miracle- a miracle SF version)
- 2014-04-12 16:34:35下载
- 积分:1
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perceptron
% 单层感知器 与、或、以及其他逻辑功能的实现
% 采用step逐步逐行运行方式,了解学习过程的细节
% 尝试重新定义程序中的T,观察感知器实现异或运算(T=1 0 1 0]的可能性。(% Implementation of Single Layer Perceptron and, or, and Other Logic Functions
% Use step-by-step operation to understand the details of the learning process
% Trying to redefine T in the program, observing the possibility of XOR operation (T = 1010) implemented by the perceptron.)
- 2020-06-20 03:40:01下载
- 积分:1
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cp3
matlab图形图像处理教程,第三章内容。供有关人员参考啊(matlab image processing tutorial, graphics, and the third chapter. Ah for the relevant Reference)
- 2011-06-13 18:10:53下载
- 积分:1
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Untitled
用于模拟电磁波在光子晶体中的传播,使用平面波展开法,利用完美耦合的吸收介质层以提高计算效率。(Used to simulate the electromagnetic wave propagation in photonic crystals using plane wave expansion method using perfect coupling absorbing medium layer to improve computational efficiency)
- 2013-03-26 12:41:55下载
- 积分:1
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kernel-ica
说明: 利用KICA实现聚类,里面含有数据集,可以进行测试(clustering with KICA)
- 2010-05-04 16:53:45下载
- 积分:1
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graph_montecarlo_single_point
蒙特卡洛法对单个空间点的分析,及正态分布检测函数(Monte Carlo analysis method for a single point in space, and the normal detection function)
- 2015-03-11 16:35:27下载
- 积分:1
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kunlao_v20
仿真效果非常好,LCMV优化设计阵列处理信号,利用贝叶斯原理估计混合logit模型的参数。( Simulation of the effect is very good, LCMV optimization design array signal processing, Bayesian parameter estimation principle mixed logit model.)
- 2016-05-27 13:30:59下载
- 积分:1
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SVMDTC_close
direct torque control of brushless dc motor based on space vector
- 2010-12-21 21:54:48下载
- 积分:1
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111
function pi = solve2(count,m,cc)
借助布冯投针实验 仿真求pi的值
pi=0
frq=0
randNo = binornd(1,cc,1,m)
pro=zeros(1,count)
for j=1:count
for i = 1:m
if randNo(1,i) == 1
frq = frq + 1
end
pro(i) = frq/i
end
pi = (2*m)/frq
pro(j) = pi
end
pro = pro,num =1:count
plot(num,pro) (function pi = solve2 (count, m, cc) to vote with Buffon needle experiment simulation find the value of pi pi = 0 frq = 0 randNo = binornd (1, cc, 1, m) pro = zeros (1, count) for j = 1: count for i = 1: m if randNo (1, i) == 1 frq = frq+ 1 end pro (i) = frq/i end pi = (2* m )/frq pro (j) = pi end pro = pro, num = 1: count plot (num, pro) )
- 2011-05-24 15:39:41下载
- 积分:1