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0和1 的随机分布 在矩阵中各占50 ，源码 可以直接运行的 (Random distribution of 0 and 1 in the matrix 50/50, source code can be run directly)

说明：  有关测量平差计算的一个很好的程序,不知大家是否对测绘学科的内容感兴趣?(adjustment calculation of the measurement of a good procedure, we do not know whether the right mapping disciplines interested in the content)

serilizatiob of binary objects into xml file and de-serialization that

1602显示程序，单片机是STC15，程序包括/* 等待液晶准备好 *//* 向LCD1602液晶写入一字节命令，cmd-待写入命令值 *//* 向LCD1602液晶写入一字节数据，dat-待写入数据值 *//* 设置显示RAM起始地址，亦即光标位置，(x,y)-对应屏幕上的字符坐标 *//* 在液晶上显示字符串，(x,y)-对应屏幕上的起始坐标，str-字符串指针 *//* 初始化1602液晶 */等。

DVB 能完整的解析出TS流文件中的PAT，PMT，NIT，CAT信息，并且能兼容188和204的TS流文件(DVB can be a complete parse out the TS stream file in the PAT, PMT, NIT, CAT information, and can be compatible with the 188 and 204 of the TS stream file)

关于CORBA 通信的描述和开发，原理和 概念 ，中文版 (The description on the CORBA communication and development, principles and concepts, the Chinese version)

有n个整数，使其前面各数顺序向后移m个位置，最后m个数变成最前面的m个数(There are n integers to the order of the preceding few months m backward shift position, the final number m into the top of the number of m)

在vc控制台中运行，用遗传算法求解最短路径，用邻接矩阵表示路线图。(Vc console in the run, the shortest path with the genetic algorithm, said the road map with the adjacency matrix.)

说明：  2008年4月网工真题.doc 对各位考生有很大的帮助，希望各位考上(April 2008 Network Engineering 真题. Doc candidates of you very helpful, hope you admitted to)

Level of Detail 层次渲染，游戏编程 根据远近关系实现进出渲染，减少资源消耗(Level of Detail-level rendering, game programming relations based on distance and out of rendering, reduce resource consumption)