shiboqi

vs2005环境下编写的sbl病毒专杀工具，可以扫描文件中的sbl病毒，并集中清除(vs2005 environment prepared by the sbl virus Zhuanshagongju, you can scan documents in the sbl-virus, and focus on clear)

提取ACCESS文件中的密码，不需要暴力破解。从文件中的某一字段直接解密(ACCESS extract document password, do not need to break the violence. From the document directly to decrypt a field)

Vc++读写csv文件的类，这个资源是读写CSV文件的非常实用的类。方法写得非常好，代码也写得非常简洁，很合适在实际项目中使用。经本人测试，只要把上面的代码CSVOperator.h、CSVOperator.cpp和StringParser.h拷贝到项目中，就可以直接使用。在CSV_OP.cpp文件中，main方法里面有详细的读取文件的方法。读取的是config.csv这个文件。(Class Vc++ read and write csv file, this resource is to read and write CSV file very useful class. The method is very good, the code is written in a very simple, very suitable for use in the actual project. I tested, above code CSVOperator.h the, CSVOperator.cpp and StringParser.h copy to the project, can be used directly. In the CSV_OP.cpp file, the main method inside the detailed method of reading the file. Read this file config.csv.)

钟面上的时针和分针之间的夹角总是在 0 ～180之间 ( 包括 0 和180 ) 。举例来说，在十二点的时候两针之间的夹角为 0 ，而在六点的时候夹角为180 ，在三点的时候为90 。本题要解决的是计算 12:00 到 11:59 之间任意一个时间的夹角。(The angle between the hour and minute hands of the clock face is always between 0 to 180 (including 0 and 180). For example, twelve o' clock, when the angle between the two pin 0, in the six o' clock when the angle is 180, three points for 90. This question must be resolved are the angle of the calculation of 12:00 to 11:59 any one time.)

谭浩强C程序设计第四版第9章习题答案,自己做出来的( C Programming Fourth Edition Chapter 9 Exercise answers, do it yourself)

软件测试功能，使用uft进行的自动化测试功能(programing test,for auto programing test by UFT)

线性表的创建 删除 查找 插入 输出等功能(linearlist create delete find insert print)

字符串交叉输入，就是将一个字符串交叉的输入到了另一个字符串当中，比如： char a[4]="ABCD" char b[4]="abcd" 则char c[8]="AaBbCcDd" (Cross-string input, is to cross a string input to another string of them, such as: char a [4] = "ABCD" char b [4] = "abcd" While char c [8] = "AaBbCcDd" )

小型VB图片管理系统（Access）,有需要的就下载吧。(Small VB Image Management System (Access), there is a need to download it.)

遍历堆，可以对一个堆编立，复制，采用函数的递归调用来实现的(Traverse the heap, the recursive call to compile a heap legislation, copy, use the function)