Chapter6

  数值解法 例1 用改进的欧拉方法求一阶方程初值问题的 数值解 例2 数学摆的运动方程与近似方程数值解比较 例3 四阶龙格库塔公式求数值解 Matlab实现求数值解 例1 求初值问题y =x*sin(x)-y,y(0)=0的数值 解.先编辑一个定义方程的ODEF函数文件 ODEfun1.m. 例2 求方程组初值问题的数值解,按指定步长 0.05划分节点. 例3 按指定的精度求高阶方程初值问题的数值解.(Numerical Solution of the law a method of using the improved Euler' s equation of order to a first-order initial value problem of the numerical solution of cases of two mathematical pendulum equations of motion compared with the approximate numerical solutions of equations of three cases of fourth-order Runge-Kutta numerical solution of the formula Matlab order to achieve the numerical solution of demand cases seeking an initial value problem y ' = x* sin (x)-y, y (0) = 0 the numerical solution. first, the definition of an equation editor ODEF function file ODEfun1.m. cases of two demand equations initial value problem of numerical solution, according to the specified division of the node step 0.05. Example 3 according to the specified precision of seeking higher-order equation of the numerical solution of initial value problem.)