Raytracing

MATLAB SIMULINK与控制系统仿真 王正林等编着(MATLAB/SIMULINK and control system)

用镜像矩阵求出矩阵的QR分解（正交三角分解），并求解线性方程组，该方法不必选主元，但其计算过程非常稳定。也可用于求矩阵的广义逆和求解线性最小二乘问题。子过程QRDCMP用镜像矩阵求m*n矩阵A的QR分解，A=Q^TR,其中Q是m*m正交矩阵，R为m*n上三角矩阵；子过程QRBKSB用矩阵的QR分解求解线性方程组Ax=b，其中A为n阶非奇异方阵。(Matrix obtained with the mirror matrix QR decomposition (orthogonal triangular decomposition), and solving linear equations, the method does not have to choose the main element, but its calculation process is very stable. Can also be used to find the generalized inverse matrix and solving linear least squares problems. Sub-process of the mirror matrix QRDCMP m* n matrix A QR decomposition, A = Q ^ TR, wherein Q is a m* m orthogonal matrix, R is m* n upper triangular matrix subprocess QRBKSB a QR decomposition to solve the matrix linear equations Ax = b, where A is non-singular square matrix of order n.)

matlab implementation of wimax downlink

Tiva C 123 Application projects

这是姜启源教授在清华大学讲解数学建模课程的资料，对于数学建模由入门到精通十分有用(lecture in math modeling,given by Professor JiangQiyuan )

大地坐标变换，转换经度很高，修改正了反变换有0.6误差的错误。下载即可使用。(Geodetic coordinate transformation, the conversion of longitude is very high, change the inverse transform has 0.6 error. You can use to download. )

int compare(const char* a, const char* b, int size) { for (int i = 0 i < size i ++) { if (a[i] != b[i]) { return i } } return -1 } (int compare(const char* a, const char* b, int size) { for (int i = 0 i < size i++) { if (a[i] != b[i]) { return i } } return-1 } )

捷联惯导姿态位置速度高度全解算，其中程序的使用还应该按需选择和衔接(SINS Attitude Full height position and speed solver, In which the program should also demand choices and Cohesion .)

基于 Matlab 的积分分离 PID 控制 算法及仿真 摘 要 MATLAB 是一种集数值计算、符号运算、可视化(flying car)

這是一個C#框架, 實現了,很smart clien功能(This is a C# framework to achieve, and it's very functional smart clien)