chapter03

这是纳米金颗粒的散射实例，在comsol环境下的仿真(nano-gold,comsol,mie scattering)

设X[ 0 : n - 1]和Y[ 0 : n – 1 ]为两个数组，每个数组中含有n个已排好序的数。找出X和Y的2n个数的中位数。  编程任务 利用分治策略试设计一个O (log n)时间的算法求出这2n个数的中位数。 数据输入 由文件input.txt提供输入数据。文件的第1行中有1个正整数n（n<=200），表示每个数组有n个数。接下来的两行分别是X，Y数组的元素。结果输出 程序运行结束时，将计算出的中位数输出到文件output.txt中(Let X [0: n- 1] and Y [0: n- 1] for the two arrays, each array containing the n number has been sorted. 2n X and Y to identify the number of digits.  programming tasks using the divide and conquer strategy try to design an O (log n) time algorithm to calculate this median number 2n. Data input by the input data provided input.txt file. The first line in the file has a positive integer n (n < = 200), that there are n numbers of each array. The next two lines are the X, Y array elements. The end result is output program runs, the calculated median output to file output.txt)

这是一个很不错的小体积的软件(This is a very good small size of software)

bump mapping with C++

数据库访问,能帮助解决很多问题的！大家可以好好学习学习。(Database access, can help solve many problems! We can learn to learn.)

说明：  很久之前收录的，并非原创。歪果仁写的免注册调用DLL的VB源码例子。(What was included a long time ago was not original. An example of VB source code for non-registered DLL calls written by crooked kernels)

DSP28335 CAN发送的例子，试验过，可以用(Examples DSP28335 CAN transmitted tested, can be used)

音乐播放器，可以从系统中选择想要听的歌曲，导入到该播放器中，播放器有暂停和开始选项。(Music player, you can choose from the system you want to listen to the songs into the player, the player with pause and start options.)

DS1302和LCD1602的组合简单应用(DS1302 and LCD1602 Application together)

让你更好理解C++的基本内容与间接提高,并且深入领会(Make you a better understanding of C++, and indirectly enhance the basic content and in-depth understanding of)