amplifier5

说明：  003yasuowenjianxingbuxing

输入椭圆中心和长短轴径; 2. 计算得到中心在原点的椭圆上的第一个点=; 3. 根据公式(1.1.3-2)计算区域1中决策参数的初值为; 4. 在区域1中每个位置处，从开始，反复按照公式(1.1.3-3)更新决策参数，若决策参数小于0则不变，反之加1，一直循环到为止，记第一个满足此条件的点为(); 5. 在区域2的每个位置处，从开始，反复按照公式(1.1.3-6)更新决策参数，若决策参数小于0则不变，反之加1，一直循环到()为止;(Input ellipse center and long and short axis diameter; 2. The first point of the center on the ellipse at the origin is calculated. 3. According to formula (1.1.3-2), the initial value of decision-making parameters in region 1 is calculated. 4. At each location in region 1, the decision-making parameters are updated repeatedly according to formula (1.1.3-3). If the decision-making parameters are less than 0, they will remain unchanged. If the decision-making parameters are less than 0, then add 1 and cycle until the first point satisfying this condition is (); 5. At each location of region 2, the decision parameters are updated repeatedly according to the formula (1.1.3-6). If the decision parameters are less than 0, they will remain unchanged. If the decision parameters are less than 0, then add 1 and cycle until ().)

这是一本嵌入式ARM的书籍，并且介绍了ARM编程方面的书籍(This is an embedded ARM book)

包含斯坦福nlp相关教程，可以察看安装教程(I just want some corpus please)

C#.NET开发的扫雷源代码-C#.NET development of the mine-source

说明：  stm32使用ra02模块的例程,点对点通讯(Stm32 USES ra02 module routines to communicate point-to-point)

C语言课程设计，银行管理系统，具有增、删、改、查等功能(C language course design, bank management system, with add, delete, change, check and other functions)

汉诺塔游戏 好久没动手写过东西了，练习的东东，还有很多问题，适合初学者学习，代码里有注释。 -HANOR hands game had not written anything, the Eastern practice, there are many problems, for beginners learning, there are code Notes.

说明：  数据库系统概念中文版，作为大学的核心课程，本书对于自学的同学非常友好，对于里面的伪代码和习题都建议同学自己去尝试。(The Chinese version of the concept of database system, as the core course of university, is very friendly to the students who teach themselves. For the pseudo-code and exercises in this book, students are advised to try it by themselves.)

Database for wago PLC controller