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lv0
玻璃切割项目最低水平线算法MATLAB源码,已通过调试(Glass cutting project MATLAB source code, has passed the commissioning)
- 2021-03-29 16:29:11下载
- 积分:1
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hgfx1
求两个数组的和差积商,其主要功能就是计算两个数组的和差积商(Find difference between two arrays and product providers)
- 2011-09-07 17:10:54下载
- 积分:1
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The-feature-detection-of-Apple
一种针对于苹果内部缺陷的检测方法和算法,利用matlab实现其功能(One for the Apple internal defect detection method and algorithm, using matlab to achieve its function)
- 2013-04-05 16:04:28下载
- 积分:1
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DMC2210-hardware
DMC2210硬件手册。该手册是DMC2210控制卡的硬件参数说明以及硬件编程所应注意的问题等。(DMC2210 hardware manual. The manual is a hardware parameter descriptions and hardware programming DMC2210 control card should pay attention to the issues.)
- 2014-01-15 12:26:40下载
- 积分:1
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UKF
介绍了UKF算法及其仿真,希望对大家能够有所帮助。(introduce the unscented kalman filtering)
- 2009-05-04 09:47:25下载
- 积分:1
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matlab-tongjifenxi
《matlab统计分析与应用:40个案例分析》一书的全部代码(Matlab statistical analysis and application: 40 case studies of a book all the code)
- 2012-08-16 11:44:06下载
- 积分:1
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guangdaizhongxintiqu
用于自动批量提取不同图像坐标位置的激光光带图像的中心,并将批量处理结果依次显示在一张输出图像中,输入为批量的激光光带图像,输出为激光中心坐标并做图显示(Different images for automatic batch extraction center coordinate positions with images of laser light, and the batch processing results in order to display the image in an output, the input for the bulk of the laser light with the image coordinates of the center and the laser output is done diagram shows)
- 2014-01-02 17:37:00下载
- 积分:1
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kalmandemo
kalman滤波的MATLABdemo,适合MATLAB初学者学习(matlab kalman)
- 2010-08-28 10:55:56下载
- 积分:1
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FourthordersolvefifthorderCNNequation
说明: 用四阶经典龙格库塔算法求解5阶细胞神经网络状态方程,得到5路超混沌序列。(With the fourth order classical Runge-Kutta algorithm for 5-order cellular neural network state equation, 5-way super-chaotic sequence are generated.)
- 2010-04-20 10:55:06下载
- 积分:1
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rayleigh_fading1
filename: rayleigh_fading.m
function: rayleigh fading
input parameters: multipath_ID (user, multipath)
output parameters: envelope
read files: no
generate files: no
call functions: no
called by: wireless_UL, wireless_DL
Execution Time: case 1: 29/100 Seconds(100 times called)(N=25)
case 2: 4.4/100 Seconds(100 times called)(N=25)
Sun Jianxun, Apr., 02, 2001
- 2014-02-18 21:09:24下载
- 积分:1